Question

以下是我的XML的样子。我试图在SQL Server 2008中查询XML。我想显示基于ID的所有声明。

<clue xmlns="http://cp.com/rules/client">
    <claim unit_number="1" number="0000007517" id="S1"
           sequence_number="1">
        <scope_of_claim>Full scope</scope_of_claim>
    </claim>
    <claim unit_number="1" number="0000007518" id="S1"
           sequence_number="2">
        <scope_of_claim>Full scope</scope_of_claim>
    </claim>
</clue>

我的查询：

以下查询仅为我提供了第一项索赔的值。

;WITH XMLNAMESPACES (DEFAULT 'http://cp.com/rules/client')
select xmldocument.value('(//claim/@number)[1]','varchar(20)') as ClaimNumber,  
       xmldocument.value('(//claim/scope_of_claim)[1]','varchar(20)') as Scope
       .....
from clue.xml

我如何获得所有索赔？

Answer 1

;WITH XMLNAMESPACES (DEFAULT 'http://cp.com/rules/client')
SELECT xmlid,
       ClaimNumber,
       Scope
FROM   clue.xml
       OUTER APPLY 
                  (SELECT 
                     tbl.col.value('(@number)[1]', 'varchar(20)') AS ClaimNumber,
                     tbl.col.value('(scope_of_claim)[1]', 'varchar(20)') AS Scope
                    FROM   xmldocument.nodes('//claim') AS tbl(col)) x

如何获取xml文件的子元素的所有值。 SQL Server 2008

1 个答案: