Question

我想在循环外获取变量输出a（在循环中）

        stopped_reasons = []
        output=[]




         client = boto3.client('ec2')
         reservations = client.describe_instances().get('Reservations', []) 

         for reservation in reservations:
             for instance in reservation['Instances']:
               tags = {}
               for tag in instance['Tags']:

                    tags[tag['Key']] = tag['Value']
                    if tag['Key'] == 'Name':
                      name=tag['Value']     
             if instance['State']['Name'] == 'stopped':

                 instance_ids.append(instance['InstanceId'])
                 instance_names.append(name)
                 stopped_reason = instance['StateTransitionReason']
                 stopped_reasons.append(stopped_reason)
                 transition_timestamp = datetime.strptime(instance['StateTransitionReason'][16:39], '%Y-%m-%d %H:%M:%S %Z')
                 #print (datetime.now() - transition_timestamp).days
                 a="Instance:"+ instance['InstanceId']  + '  Name: ' +name + "TIME: "+str(transition_timestamp)
                 print a
                 output.append(a)

print output

打印一个（内部循环）给出我想要的：

Instance:i-03666a1aea6028cf0  Name: aws-opsworks-cm-instance-mypuppet-1541455366196TIME: 2018-11-15 18:30:27
Instance:i-0a67100fa09eab573  Name: Choco_ServerTIME: 2018-11-29 18:30:27

我正在尝试获得相同的输出，但在for循环之外。所以我声明了列表输出并附加了一个变量

但打印输出（外部循环）仅占一行

['Instance:i-03666a1aea6028cf0  Name: aws-opsworks-cm-instance-mypuppet-1541455366196 TIME: 2018-11-15 18:30:27', 'Instance:i-0a67100fa09eab573  Name: Choco_Server TIME: 2018-11-29 18:30:27']

Answer 1

刚刚找到它，必须将新行添加到列表中

 body= "\n".join(output)
 print body

Answer 2

请注意，您正在使用output.append(a)-output是一个列表。在一般的python打印列表中，就像您在此处看到的那样：全部一行，带有方括号，并在字符串两边加上引号。

如果要单独打印每行而不使用引号，则必须单独打印列表的每个元素，而不是一次打印整个列表。代替

print output

做

for line in output:
    print line

获取循环Python之外的值列表

2 个答案: