如果一行中有2个相同的单词，请使用sed将第二个单词更改为“ jinx”

Question

例如：我唯一的目标就是在比赛中进球。

const villages = { "lossesOccured": [{ "type": "destroyed", "affectedOn": "humans", "quantity": 120, "reliefFund": 100000, "location": { "district": "thanjavur", "villageName": "madukkur", "pincode": "614903" } }, { "type": "physicalDamage", "affectedOn": "humans", "quantity": 250, "reliefFund": 50000, "location": { "district": "thanjavur", "villageName": "madukkur", "pincode": "614903" } }, ] } const lossesArray = villages.lossesOccured const myMap = new Map(); lossesArray.forEach(loss => { if (loss.affectedOn === "humans") { myMap.set({ key: loss.affectedOn }, loss); } }); console.log(myMap);

两个词之间应有一个或多个词。

Answer 1

$ echo "My only goal is to score a goal in the match" | \
  sed -r 's/(\b\w+\b)(.*\w+.*)\1/\1\2jinx/g'
My only goal is to score a jinx in the match

• -r激活扩展的posix regular expressions。注意：使用基本posix正则表达式时，您必须转义括号，例如：\(....\)和+运算符不存在
• (\b\w+\b)匹配一个单词

• (.*\w+.*)捕获介于两者之间的所有内容

• \1匹配第一个括号，\2匹配第二个括号

• g代表全局，否则将只更改第一个匹配项。

因此，(\b\w+\b)(.*\w+.*)\1/将发现同一单词出现两次的行

然后\1\2jinx将用jinx替换第二次出现的\1