Question

我具有此功能，它将在控制台上返回结果：

numbers_to_add = list(range(10000001))
try:
    req = request.Request('http://127.0.0.1:5000/total'
        , data=bytes(json.dumps(numbers_to_add), 'utf_8')
        , headers={'Content-Type': 'application/json'}
        , method='POST')
    result = json.loads(request.urlopen(req).read(), encoding='utf_8')
    print(json.dumps(result, indent=4))
except Exception as ex:
    print(ex)

它返回范围10000001

上的结果

现在，我想在浏览器请求中返回此值，在Flask应用程序中，我已经尝试过：

def hardCoded():
    numbers_to_add = list(range(10000001))
    try:
        req = request.Request('http://127.0.0.1:5000/total'
            , data=bytes(json.dumps(numbers_to_add), 'utf_8')
            , headers={'Content-Type': 'application/json'}
            , method='POST')
        result = json.loads(request.urlopen(req).read(), encoding='utf_8')
        print(json.dumps(result, indent=4))
    except Exception as ex:
        print(ex)

class rangeNumbers(Resource):
    def get(self, range):
        return {'data': directSum.hardCoded(range)}

api.add_resource(rangeNumbers, '/range/<range>')

当我在浏览器中查询此消息时，它会向我抛出该消息：

Traceback (most recent call last):
File "/home/user/.virtualenvs/test_sum/lib/python3.6/site-packages/flask/app.py", line 1612, in full_dispatch_request
rv = self.dispatch_request()
File "/home/user/.virtualenvs/test_sum/lib/python3.6/site-packages/flask/app.py", line 1598, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "/home/user/.virtualenvs/test_sum/lib/python3.6/site-packages/flask_restful/__init__.py", line 480, in wrapper
resp = resource(*args, **kwargs)
File "/home/user/.virtualenvs/test_sum/lib/python3.6/site-packages/flask/views.py", line 84, in view
return self.dispatch_request(*args, **kwargs)
File "/home/user/.virtualenvs/test_sum/lib/python3.6/site-packages/flask_restful/__init__.py", line 595, in dispatch_request
resp = meth(*args, **kwargs)
File "app.py", line 16, in get
return {'data': directSum.hardCoded()}
TypeError: hardCoded() takes 0 positional arguments but 1 was given

有什么想法吗？

Answer 1

如果range是要返回的n数字（在这种情况下为10000001），那么您将需要这样做：

在您的directSum文件中：

def hardCoded(rng):
    numbers_to_add = list(range(rng))
    try:
    # ... rest of code ...

在您的主文件中：

class rangeNumbers(Resource):
    def get(self, rng):
        return {'data': directSum.hardCoded(rng)}

在致电rangeNumbers().get时，您可以这样做：

rng_num = rangeNumbers()
rng_num.get(10000001)

注意，我将变量range更改为rng。即使在本地范围内，不要遮盖builtin名称也符合您的最大利益。否则致电range(range)会让您无尽的痛苦。

在浏览器上返回json-Flask

1 个答案: