如果在SUT的另一部分抛出异常(异步流),则测试失败

时间:2018-11-28 09:46:17

标签: c# unit-testing testing moq

我有这样的系统

class Sut
{
    IRepository _repo;

    public Sut(IRepository repo) { _repo = repo; }

    async Task Handle(Request request)
    {
         var entity  = new Entity(request.Id); //=> if Id is not ok the Entity throws Exception

         _repo.Save(entity);
    }
}

这是测试

[Fact]
public async Task Test_Save()
{
    Mock<IRepository> repositoryMock = new Mock<IRepository>();

    repositoryMock
        .Setup(repo => repo.Save(It.IsAny<Entity>()))
        .Returns(Task.CompletedTask);

    var sut = new Sut(repositoryMock.Object);

    /// Act
    Action action = async () => await sut.Handle(new Request { Id = default(Guid)});

    /// Assert 
    Assert.Throws<Exception>(action);
    repositoryMock.Verify(repo => repo.Save(It.IsAny<Entity>(), Times.Never);
}

因此,Entity会检查是否有默认值Guid传递给它。如果通过默认值,将抛出异常。

引发了异常,但测试失败并显示此消息。

  

消息:Assert.Throws()

     

预期失败:typeof(System.Exception)

     

实际:(没有引发异常)

测试永远不会调用

repositoryMock.Verify(repo => repo.Save(It.IsAny<Entity>(), Times.Never);

它将在此行中断

为什么?如何解决这种情况?

Assert.Throws<Exception>(action);

更新

 public Entity(Guid id)
 {
     if (default(Guid) == id) throw new Exception("cannot have a default value for id");
     Id = id;
 }

1 个答案:

答案 0 :(得分:4)

Action action = async () => ...基本上是async void,这意味着抛出的异常不会被捕获。

更改语法以与Func<Task>一起使用Assert.ThrowsAsync

[Fact]
public async Task Test_Save() {
    //Arrange
    var repositoryMock = new Mock<IRepository>();

    repositoryMock
        .Setup(repo => repo.Save(It.IsAny<Entity>()))
        .Returns(Task.CompletedTask);

    var sut = new Sut(repositoryMock.Object);

    /// Act
    AsyncTestDelegate act = () => sut.Handle(new Request { Id = default(Guid)});

    /// Assert 
    await Assert.ThrowsAsync<Exception>(act);
    repositoryMock.Verify(repo => repo.Save(It.IsAny<Entity>(), Times.Never);
}

引用Assert.ThrowsAsync