Question

这是我在stackoverflow中的第一个问题，对我很好：）

我有一个具有列族的表，当我进行查询（带有where语句）时，我想将结果显示为一组具有相同族的行

例如，表为shop：

+----+--------+-------+
| id | family | money |
+----+--------+-------+
|  1 |      1 |   100 |
|  2 |      1 |    70 |
|  3 |      2 |    10 |
|  4 |      2 |    20 |
|  5 |      3 |    50 |
+----+--------+-------+

所以我想要在执行这样的查询时：

SELECT * FROM shop where money=100 --(adding to the query of course what's needed)

它将选择这两个：

+-----+----------+---------+
| id  |  family  |  money  |
+-----+----------+---------+
| 1   |       1  |    100  |
| 2   |       1  |     70  |
+-----+----------+---------+

Answer 1

您可以使用in或exists：

SELECT s.*
FROM shop 
WHERE s.family IN (SELECT s2.family FROM shop s2 WHERE s2.money = 100);

Answer 2

您可以将Correlated Subquery与Exists()一起使用：

SELECT
  t1.*
FROM shop t1
WHERE EXISTS (SELECT 1 FROM shop t2
              WHERE t2.family = t1.family AND 
                    t2.money = 100)

用SQL按族返回行

2 个答案: