Question

有人可以帮助我将此cURL命令转换为Go吗？

curl -X PUT -H 'Content-Type: image/jpg' \
     -H "Content-Length: 132093" \
     -T "/Users/ikmal/Downloads/catcute.jpg" \
     "https://hootsuite-video.s3.amazonaws.com/production/18395606_a9245dd7-73d6-4392-af4a-1cd9bf359cfb.jpg?AWSAccessKeyId=AKIAIM7ASX2JTE3ZFAAA&Expires=1543304067&Signature=n9sZkQ%2BF1DGuiYHqixrrvmoxIXQ%3D"

我已经尝试过生成器了，

1。 https://mholt.github.io/curl-to-go/

它创建了这样的Go代码：

// Generated by curl-to-Go: https://mholt.github.io/curl-to-go

req, err := http.NewRequest("PUT", "https://hootsuite-video.s3.amazonaws.com/production/18395606_a9245dd7-73d6-4392-af4a-1cd9bf359cfb.jpg?AWSAccessKeyId=AKIAIM7ASX2JTE3ZFAAA&Expires=1543304067&Signature=n9sZkQ%2BF1DGuiYHqixrrvmoxIXQ%3D", nil)
if err != nil {
    // handle err
}
req.Header.Set("Content-Type", "image/jpg")
req.Header.Set("Content-Length", "132093")

resp, err := http.DefaultClient.Do(req)
if err != nil {
    // handle err
}
defer resp.Body.Close()

2。 https://curl.trillworks.com/

它创建了这样的Go代码：

package main

import (
    "fmt"
    "io/ioutil"
    "log"
    "net/http"
)

func main() {
    client := &http.Client{}
    req, err := http.NewRequest("PUT", "https://hootsuite-video.s3.amazonaws.com/production/18395606_a9245dd7-73d6-4392-af4a-1cd9bf359cfb.jpg?AWSAccessKeyId=AKIAIM7ASX2JTE3ZFAAA&Expires=1543304067&Signature=n9sZkQ%2BF1DGuiYHqixrrvmoxIXQ%3D", nil)
    if err != nil {
        log.Fatal(err)
    }
    req.Header.Set("Content-Type", "image/jpg")
    req.Header.Set("Content-Length", "132093")
    resp, err := client.Do(req)
    if err != nil {
        log.Fatal(err)
    }
    bodyText, err := ioutil.ReadAll(resp.Body)
    if err != nil {
        log.Fatal(err)
    }
    fmt.Printf("%s\n", bodyText)
}

但是都没有给我正确的代码，因为当我在项目上运行这些代码时，它会返回一些错误，因为它不会生成此部分：

-T "/Users/ikmal/Downloads/catcute.jpg"

并将其生成为“ nil”。

更新：

针对此问题，我所做的就是添加以下代码：

file, err := os.Open("/Users/ikmal/Downloads/catcute.jpg")
if err != nil {
    panic(err)
}
defer file.Close()

所以我将变量“ file”放入正文请求中，这是我的最终代码：

func main(){
    file, err := os.Open("/Users/ikmal/Downloads/catcute.jpg")
    if err != nil {
        panic(err)
    }
    defer file.Close()

    client := &http.Client{}
    req, err := http.NewRequest("PUT", "https://hootsuite-video.s3.amazonaws.com/production/18395606_a9245dd7-73d6-4392-af4a-1cd9bf359cfb.jpg?AWSAccessKeyId=AKIAIM7ASX2JTE3ZFAAA&Expires=1543304067&Signature=n9sZkQ%2BF1DGuiYHqixrrvmoxIXQ%3D", file)
    if err != nil {
        log.Fatal(err)
    }
    req.Header.Set("Content-Type", "image/jpg")
    req.Header.Set("Content-Length", "132093")
    resp, err := client.Do(req)
    if err != nil {
        log.Fatal(err)
    }
    bodyText, err := ioutil.ReadAll(resp.Body)
    if err != nil {
        log.Fatal(err)
    }
    fmt.Printf("%s\n", bodyText)
}

然后，当我构建并运行该程序时，它将返回如下响应：

<?xml version="1.0" encoding="UTF-8"?>
<Error>
   <Code>NotImplemented</Code>
   <Message>A header you provided implies functionality that is not implemented</Message>
   <Header>Transfer-Encoding</Header>
   <RequestId>FBD2CEAF71EA4DEA</RequestId>
   <HostId>K6hDrHIJr5YtoIBn2d64bfuLBgs6F17gKQV9jrTJ31X987A5gshhqtnKDs3lW2uSliBJwk1pri4=</HostId>
</Error>

错误似乎来自标题问题，但我确定我正确键入了标题。我错过了什么地方吗？

Answer 1

您必须使用multipart上传图像内容。

f, err := os.Open("./Users/ikmal/Downloads/catcute.jpg")
if err != nil{
    log.Fatal(err)
}
defer f.Close()

var buf = new(bytes.Buffer)
writer := multipart.NewWriter(buf)

part, _ := writer.CreateFormFile("image", "dont care about name")
io.Copy(part, f)

writer.Close()

req, _ := http.NewRequest("POST", "https://hootsuite-video.s3.amazonaws.com/production/18395606_a9245dd7-73d6-4392-af4a-1cd9bf359cfb.jpg?AWSAccessKeyId=AKIAIM7ASX2JTE3ZFAAA&Expires=1543304067&Signature=n9sZkQ%2BF1DGuiYHqixrrvmoxIXQ%3D", buf)
req.Header.Set("Content-Type", writer.FormDataContentType())

client := &http.Client{}
res, _ := client.Do(req)
defer res.Body.Close()
b, _ := ioutil.ReadAll(res.Body)
fmt.Println(string(b))

如何使用文件作为正文复制cURL命令

1 个答案: