我正在工作,但是我想与大家分享一下,看是否遗漏了任何明显的东西,并解决了为什么我的文件块大小必须是2049的倍数的谜。主要要求是:
在这里,我将专注于下载部分。基本上我正在做的是:
返回带有数据块的数据集的VB库函数(我必须使用该库来处理数据库连接,但不支持参数查询)
Public Function GetWebApplicationAttachment(ByVal intId As Integer, ByVal intChunkNumber As Integer, ByVal intChunkSize As Integer) As DataSet
' the starting number is NOT 0 based
Dim intStart As Integer = 1
If intChunkNumber > 1 Then intStart = ((intChunkNumber - 1) * intChunkSize) + 1
Dim strQuery As String = ""
strQuery += "SELECT FileName, "
strQuery += "SUBSTRING(ByteData," & intStart.ToString & "," & intChunkSize.ToString & ") AS ByteData "
strQuery += "FROM FileAttachments WHERE Id = " + intId.ToString + " "
Try
Return Query(strQuery)
Catch ex As Exception
...
End Try
End Function
可从数据集中创建文件对象的Web API业务规则位
...
result.FileName = ds.Tables[0].Rows[0]["FileName"].ToString();
// NOTE: Web API converts a byte array to base 64 string so the result is the same either way
// the result of this is that the returned data will be about 30% bigger than the chunk size requested
result.StringData = Convert.ToBase64String((byte[])ds.Tables[0].Rows[0]["ByteData"]);
//result.ByteData = (byte[])ds.Tables[0].Rows[0]["ByteData"];
... some code to get the mime type
result.MIMEType = ...
Web API控制器(已简化-删除了所有安全性和错误处理)
public IHttpActionResult GetFileAttachment([FromUri] int id, int chunkSize, int chunkNumber) {
brs = new Files(...);
fileResult file = brs.GetFileAttachment(appID, chunkNumber, chunkSize);
return Ok(file);
}
angularjs服务,以递归方式获取块并将它们放在一起
function getFileAttachment2(id, chunkSize, chunkNumber, def, fileData, mimeType) {
var deferred = def || $q.defer();
$http.get(webServicesPath + "api/files/get-file-attachment?id=" + id + "&chunkSize=" + chunkSize + "&chunkNumber=" + chunkNumber).then(
function (response) {
// when completed string data will be empty
if (response.data.StringData === "") {
response.data.MIMEType = mimeType;
response.data.StringData = fileData;
deferred.resolve(response.data);
} else {
if (chunkNumber === 1) {
// only the first chunk computes the mime type
mimeType = response.data.MIMEType;
}
fileData += response.data.StringData;
chunkNumber += 1;
getFileAttachment2(appID, detailID, orgID, GUID, type, chunkSize, chunkNumber, deferred, fileData, mimeType);
}
},
function (response) {
... error stuff
}
);
return deferred.promise;
}
进行调用的角度控制器方法。
function viewFile(id) {
sharedInfo.getWebPortalSetting("FileChunkSize").then(function (result) {
// chunk size must be a multiple of 2049 ???
var chunkSize = 0;
if (result !== null) chunkSize = parseInt(result);
fileHelper.getFileAttachment2(id, chunkSize, 1, null, "", "").then(function (result) {
if (result.error === null) {
if (!fileHelper.viewAsFile(result.StringData, result.FileName, result.MIMEType)) {
... error
}
result = {};
} else {
... error;
}
});
});
}
最后是一段javascript,它将文件显示为下载内容
function viewAsFile(fileData, fileName, fileType) {
try {
fileData = window.atob(fileData);
var ab = new ArrayBuffer(fileData.length);
var ia = new Uint8Array(ab); // ia provides window into array buffer
for (var i = 0; i < fileData.length; i++) {
ia[i] = fileData.charCodeAt(i);
}
var file = new Blob([ab], { type: fileType });
fileData = "";
if (window.navigator.msSaveOrOpenBlob) // IE10+
window.navigator.msSaveOrOpenBlob(file, fileName);
else { // Others
var a = document.createElement("a"),
url = URL.createObjectURL(file);
a.href = url;
a.download = fileName;
document.body.appendChild(a);
a.click();
setTimeout(function () {
document.body.removeChild(a);
window.URL.revokeObjectURL(url);
}, 0);
}
return true;
} catch (e) {
... error stuff
}
}
我已经看到一种更RESTful的方法是使用标头来指示块范围,并将文件元数据与文件块分开。我也可以尝试返回数据流而不是Base64编码的字符串。如果有人对此有提示,请告诉我。
答案 0 :(得分:0)
那完全是错误的方法。万一这有帮助,这就是我最终要做的事情。
这是更快,更可靠的方法,但是进度监控的方式却很少。
业务规则方法使用...
...
file.ByteData = (byte[])ds.Tables[0].Rows[0]["ByteData"];
...
网络api控制器
public HttpResponseMessage ViewFileAttachment([FromUri] int id, string token) {
HttpResponseMessage response = new HttpResponseMessage();
... security stuff
fileInfoClass file = ... code to get file info
response.Content = new ByteArrayContent(file.ByteData);
response.Content.Headers.ContentDisposition =
new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment") {
FileName = file.FileName
};
response.Content.Headers.ContentType = new MediaTypeHeaderValue(file.MIMEType);
return response;
甚至可以通过流媒体对此进行改进