很抱歉,如果这是一个新手问题,但我在stackoverflow上找不到此特定问题的答案。 我有一个(很大)固定宽度的数据文件,如下所示: simplefile.txt
[['This', 'is', 'the', '1st', 'line', '!'], ['This', 'is', 'the', '2nd', 'line', '.'], ['This', 'is', 'the', '3rd', 'line', '?'], ['This', 'is', 'the', '4th', 'line'], ['This', 'is', 'the', '5th', 'line', '.']]
我正在尝试使用如下所示的终端(该文件对于Excel而言太大)将其转换为csv文件:
ratno fdate ratname typecode country
12346 31/12/2010 HARTZ 4 UNITED STATES
12444 31/12/2010 CHRISTIE 5 UNITED STATES
12527 31/12/2010 HILL AIR 4 UNITED STATES
15000 31/12/2010 TOKUGAVA INC. 5 JAPAN
37700 31/12/2010 HARTLAND 1 UNITED KINGDOM
37700 31/12/2010 WILDER 1 UNITED STATES
18935 31/12/2010 FLOWERS FINAL SERVICES INC 5 UNITED STATES
37700 31/12/2010 MAPLE CORPORATION 1 CANADA
48614 31/12/2010 SERIAL MGMT L.P. 5 UNITED STATES
1373 31/12/2010 AMORE MGMT GROUP N A 1 UNITED STATES
我在此站点上进行了一些挖掘,发现了一种可能的解决方案,该解决方案依赖于ratno,fdate,ratname,typecode,country
12346,31/12/2010,HARTZ,4,UNITED STATES
12444,31/12/2010,CHRISTIE,5,UNITED STATES
12527,31/12/2010,HILL AIR,4,UNITED STATES
15000,31/12/2010,TOKUGAVA INC.,5,JAPAN
37700,31/12/2010,HARTLAND,1,UNITED KINGDOM
37700,31/12/2010,WILDER,1,UNITED STATES
18935,31/12/2010,FLOWERS FINAL SERVICES INC,5,UNITED STATES
37700,31/12/2010,MAPLE CORPORATION,1,CANADA
48614,31/12/2010,SERIAL MGMT L.P.,5,UNITED STATES
1373,31/12/2010,AMORE MGMT GROUP N A,1,UNITED STATES
shell命令:
awk
但是,当我在终端中执行上述命令时,它会无意间在所有空白中插入逗号,而这些空白应该放在单个字段中。以上执行的结果如下:
awk -v FIELDWIDTHS="5 11 31 9 16" -v OFS=',' '{$1=$1;print}' "simpletestfile.txt"
如何避免在限定的字段宽度之外的空白中插入逗号?谢谢!
答案 0 :(得分:1)
您的尝试很好,但是需要FIELDWDTHS内置变量使用gawk(gnu awk)。使用gawk:
$ gawk -v FIELDWIDTHS="5 11 31 9 16" -v OFS=',' '{$1=$1;print}' file
ratno, fdate, ratname , typecode, country
12346, 31/12/2010, HARTZ , 4 , UNITED STATES
12444, 31/12/2010, CHRISTIE , 5 , UNITED STATES
12527, 31/12/2010, HILL AIR , 4 , UNITED STATES
假设您不需要多余的空格,可以改为:
$ gawk -v FIELDWIDTHS="5 11 31 9 16" -v OFS=',' '{for (i=1; i<=NF; ++i) gsub(/^ *| *$/, "", $i)}1' file
ratno,fdate,ratname,typecode,country
12346,31/12/2010,HARTZ,4,UNITED STATES
12444,31/12/2010,CHRISTIE,5,UNITED STATES
12527,31/12/2010,HILL AIR,4,UNITED STATES
如果您没有gnu awk,则可以使用以下方法获得相同的结果:
$ awk -v fieldwidths="5 11 31 9 16" '
BEGIN { OFS=","; split(fieldwidths, widths) }
{
rec = $0
$0 = ""
start = 1;
for (i=1; i<=length(widths); ++i) {
$i = substr(rec, start, widths[i])
gsub(/^ *| *$/, "", $i)
start += widths[i]
}
}1' file
ratno,fdate,ratname,typecode,country
12346,31/12/2010,HARTZ,4,UNITED STATES
12444,31/12/2010,CHRISTIE,5,UNITED STATES
12527,31/12/2010,HILL AIR,4,UNITED STATES
答案 1 :(得分:0)
这里的perl很方便:
perl -nE ' # read this bottom to top
say join ",",
map {s/^\s+|\s+$//g; $_} # trim leading/trailing whitespace
/^(.{5}) (.{10}) (.{30}) (.{8}) (.*)/ # extract the fields
' simplefile.txt
ratno,fdate,ratname,typecode,country
12346,31/12/2010,HARTZ,4,UNITED STATES
12444,31/12/2010,CHRISTIE,5,UNITED STATES
12527,31/12/2010,HILL AIR,4,UNITED STATES
15000,31/12/2010,TOKUGAVA INC.,5,JAPAN
37700,31/12/2010,HARTLAND,1,UNITED KINGDOM
37700,31/12/2010,WILDER,1,UNITED STATES
18935,31/12/2010,FLOWERS FINAL SERVICES INC,5,UNITED STATES
37700,31/12/2010,MAPLE CORPORATION,1,CANADA
48614,31/12/2010,SERIAL MGMT L.P.,5,UNITED STATES
1373,31/12/2010,AMORE MGMT GROUP N A,1,UNITED STATES
尽管如此,对于正确的CSV,我们需要对包含逗号或引号的字段保持谨慎。如果我对文件的内容不太安全,可以使用以下map
块:
map {s/^\s+|\s+$//g; s/"/""/g; qq("$_")}
输出
"ratno","fdate","ratname","typecode","country"
"12346","31/12/2010","HARTZ","4","UNITED STATES"
"12444","31/12/2010","CHRISTIE","5","UNITED STATES"
"12527","31/12/2010","HILL AIR","4","UNITED STATES"
"15000","31/12/2010","TOKUGAVA INC.","5","JAPAN"
"37700","31/12/2010","HARTLAND","1","UNITED KINGDOM"
"37700","31/12/2010","WILDER","1","UNITED STATES"
"18935","31/12/2010","FLOWERS FINAL SERVICES INC","5","UNITED STATES"
"37700","31/12/2010","MAPLE CORPORATION","1","CANADA"
"48614","31/12/2010","SERIAL MGMT L.P.","5","UNITED STATES"
"1373","31/12/2010","AMORE MGMT GROUP N A","1","UNITED STATES"