Question

我对其进行了重新排列，使其符合要求，但是在运行代码时，它返回“对'Power（int，int，int）的未定义引用”。我将其简化为一行，但是我不知道如何解决它。将其与我所做的类似示例进行比较似乎是有条理的。我相信问题在于它没有将“返回”传递回主体。

#include <iostream>

int Power( /* in */ int pow, /* in */ int x, /* out */ int &result);    //prototype

using namespace std;

int main()
{
    int pow;
    int x;
    int result;

    cout << "Enter power: ";    //prompt for integer in for power to be raised by
    cin >> pow;                 //integer in
    cout << "Enter value to be raised to power: ";      //prompt for integer to be raised
    cin >> x;                   //integer in
    cout << Power(pow, x, result);      /*function results output.  returns input of Power function***
                                           This line is the problem but why...
                                           If I remove "(pow,x,result)" it will compile but it does not calculate properly.
                                           If I take the while loop from the Power function by itself it calculates fine.
                                           If I replace Power ((pow,x,result) with 'result' it makes a really big number...
                                         */

    return 0;                   //return
}

int Power( /*in */ int pow, /*in */ int x, /*out */ int result);        //Power function     should calculate the result of raising 'x' to the 'pow' entered...
{
    result = 1;                 //result is set at 1     by default
    while (pow > 0)             //while loop with pow set     to greater than 0
    {
        result = result * x;    //calculation for raising x by pow
        pow--;
    }
    return result;              //returning while loop results to function
}

Answer 1

声明

<div class="container">
                <img src="..." alt="Profile image" class="profileImg">
                <div class="overlay">
                    <i class="fas fa-pencil-alt text"></i>
                </div>
            </div>

与定义不符

int Power(/* in */int pow,/* in */int x,/* out */int &result);

此外，该定义的末尾有一个int Power(/*in*/int pow,/*in*/int x,/*out*/int result);，不应在该位置。您可以尝试将其更改为：

但是我建议您改用int Power(/*in*/int pow,/*in*/int x,/*out*/int& result)。

Answer 2

为什么要传递结果地址？我建议您从函数参数和主作用域中的变量中删除结果变量，这将解决该问题。

int power(int pow,int x);
int main(){
    int pow,x;
    // Get the pow and number and the index, you wrote it

    cout << "Enter power: "; //prompt for integer in for power to be raised by 
    cin >> pow; //integer in 
    cout << "Enter value to be raised to power: "; 
    cin >> x;
    cout << Power(pow,x);
// If you want to store the result do
    int result = Power(pow,x);
}
int Power(int pow,int x){
   int result = 1; //result is set at 1 by default , you want to declare result here
while(pow > 0){
    result = result * x; 
    pow--; } 
return result;  }

问题是您的定义中包含int &result，但您将其声明为int result。上面的代码解决了您的问题，使您不必定义变量结果并将其传递给Power

重写基本程序，以便它使用参数和参数代替全局变量

2 个答案: