下面的生产者消费者代码显示了错误的顺序(在生产者生产消费者消费之前。有时生产者生产许多物品(储藏室只允许一件))。为什么呢?
public class CubbyHole {
private int content;
private boolean available=false;
public synchronized int get() {
while (available == false) {
try {
wait();
} catch (InterruptedException e) {}
}
available = false;
notify();
return content;
}
public synchronized void put(int value) {
while (available == true) {
try {
wait();
} catch (InterruptedException e) { }
}
content = value;
available = true;
notifyAll();
}
}
public class Consumer extends Thread {
CubbyHole c;
public Consumer(CubbyHole c){
this.c=c;
}
public void run(){
int val=0;
for(int i =0;i<10;i++){
val=c.get();
System.out.println("consumer gets "+val);
}
}
}
public class Producer extends Thread {
CubbyHole c;
public Producer(CubbyHole c){
this.c=c;
}
public void run(){
for(int i=0;i<10;i++){
c.put(i);
System.out.println("Producer puts "+i);
}
}
}
public class Dimo {
public static void main(String[] args) {
CubbyHole c = new CubbyHole();
Producer p = new Producer(c);
Consumer con = new Consumer(c);
p.start();
con.start();
}
}
此代码获得以下输出
Producer puts 0
Producer puts 1
consumer gets 0
consumer gets 1
Producer puts 2
Producer puts 3
consumer gets 2
consumer gets 3
Producer puts 4
consumer gets 4
consumer gets 5
Producer puts 5
Producer puts 6
consumer gets 6
Producer puts 7
Producer puts 8
consumer gets 7
consumer gets 8
Producer puts 9
consumer gets 9
任何人都可以解释这段代码有什么问题吗?如何在此代码中获得正确的订单?
答案 0 :(得分:0)
检查这两行:
val=c.get();
System.out.println("consumer gets "+val);
可能发生的事情是,消费者呼叫了小孔并在其空闲时在那里等待。然后,它获取值并释放它。现在在这两行之间-在c.get()之后,在printlin之前,另一个线程可以完成其整个过程-调用put(i)并进行打印。届时,您将获得两个producer.put()值。
您应将打印零件移至立体孔代码中,以确保其打印所需的内容。