我正在从事一个实习项目,尽管它不专注于绩效,但我希望尽快(精益)。到目前为止,我有一个工作版本(带有错误)和上述功能的一个概念:
V1(错误:无法处理带点和逗号的数字。)
function addCommas(nStr) {
if (isNaN(nStr)) {
throw new Error(`${nStr} is NaN`);
}
// Alternative: isNaN(nStr) ? throw new Error(`${nStr} is NaN`) : nStr += ``;
nStr += ``;
// If the input is of the form 'xxxx.yyy', split it into x1 = 'xxxx'
// and x2 = '.yyy'.
let x = nStr.split(`.`);
let x1 = x[0];
let x2 = x.length > 1 ? `.` + x[1] : ``;
let rgx = /(\d+)(\d{3})/;
while (rgx.test(x1)) {
// x1 takes the form 'x,xxx' - no matter how long the number,
// this is where the commas are added after every three digits.
x1 = x1.replace(rgx, `$1` + `,` + `$2`);
}
return x1 + x2;
}
V2概念(外观较慢,但没有已知的错误)
function addCommas(nStr) {
if (isNaN(nStr)) {
throw new Error(`${nStr} is NaN`);
}
nStr += ``;
// Remove any potential dots and commas.
nStr = nStr.replace(`.`, ``);
nStr = nStr.replace(`,`, ``);
// Split the number into an array of digits using String.prototype.split().
// Iterate digits. After every three, add a comma.
// Transform back into a string.
return nStr;
}
答案 0 :(得分:2)
签出函数toLocaleString:
const b = 5120312039;
console.log(b.toLocaleString()); //"5,120,312,039"
答案 1 :(得分:0)
尝试一下
var str = "123456789";
var result = [...str].map((d, i) => i % 3 == 0 && i > 0 ? ','+d : d).join('').trim();
console.log(result);