现在我有这个:
<style>
table {
border-spacing: 0;
width: 100%;
border: 1px solid #ddd;
}
th, td {
text-align: left;
padding: 16px;
}
tr:nth-child(even) {
background-color: #f2f2f2
}
</style>
<table id="schInfoTable">
<thead>
<th onclick="sortTable(0)">Date</th>
<th>Amount</th>
<th>Count</th>
</thead>
<tbody>
<tr>
<td><a onclick="openView('2018-11-14')">2018-11-14</a></td>
<td>$23,000.00</td>
<td>12</td>
</tr>
<tr style="display:none; background-color: #cbe7cb;" class="2018-11-14">
<td>Mandy</td>
<td>Designer</td>
<td>View</td>
</tr>
<tr style="display:none; background-color: #cbe7cb;" class="2018-11-14">
<td>Robert</td>
<td>Cook</td>
<td>View</td>
</tr>
<tr>
<td><a onclick="openView('2018-11-13')">2018-11-13</a></td>
<td>$13,000.00</td>
<td>8</td>
</tr>
<tr style="display:none; background-color: #cbe7cb;" class="2018-11-13 branches">
<td>James</td>
<td>Driver</td>
<td>View</td>
</tr>
</tbody>
</table>
<script>
function openView(showID){
$("."+showID).toggle();
}
function sortTable(n) {
var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0;
table = document.getElementById("schInfoTable");
switching = true;
//Set the sorting direction to ascending:
dir = "asc";
/*Make a loop that will continue until
no switching has been done:*/
while (switching) {
//start by saying: no switching is done:
switching = false;
rows = table.rows;
/*Loop through all table rows (except the
first, which contains table headers):*/
for (i = 1; i < (rows.length - 1); i++) {
//start by saying there should be no switching:
shouldSwitch = false;
/*Get the two elements you want to compare,
one from current row and one from the next:*/
x = rows[i].getElementsByTagName("TD")[n];
y = rows[i + 1].getElementsByTagName("TD")[n];
/*check if the two rows should switch place,
based on the direction, asc or desc:*/
if (dir == "asc") {
if (x.innerHTML.toLowerCase() > y.innerHTML.toLowerCase()) {
//if so, mark as a switch and break the loop:
shouldSwitch= true;
break;
}
} else if (dir == "desc") {
if (x.innerHTML.toLowerCase() < y.innerHTML.toLowerCase()) {
//if so, mark as a switch and break the loop:
shouldSwitch = true;
break;
}
}
}
if (shouldSwitch) {
/*If a switch has been marked, make the switch
and mark that a switch has been done:*/
rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
switching = true;
//Each time a switch is done, increase this count by 1:
switchcount ++;
} else {
/*If no switching has been done AND the direction is "asc",
set the direction to "desc" and run the while loop again.*/
if (switchcount == 0 && dir == "asc") {
dir = "desc";
switching = true;
}
}
}
}
</script>
jsfiddle代码在这里:jsfiddle
但是,当您单击“日期”标题以按日期排序时,一切都会出错:
如您所见,绿色突出显示的表格数据一起放在底部,但是它们应该像这样:
我该如何实现?
更新:由于使用了David784的代码,因此我能够获得理想的结果,尽管不得不多花了t周的时间,但一切都归功于David。这是我现在拥有的:
function openView(showID) {
$("." + showID).toggle();
}
function sortTable(n) {
var table, rows, i, x, y = 0;
var compare1, compare2;
table = document.getElementById("schInfoTable");
switching = true;
rows = table.querySelectorAll('tr.sort');
var sortArr = [];
for (i = 0; i < rows.length; i++) {
x = rows[i];
if (i + 1 in rows) y = rows[i + 1].previousElementSibling;
else y = x.parentElement.lastChild;
var obj = {
sort: x.getElementsByTagName("TD")[n].textContent.toLowerCase(),
range: document.createRange()
};
obj.range.setStartBefore(x);
obj.range.setEndAfter(y);
sortArr.push(obj);
}
function fnSortArrAsc(a, b) {
if (a.sort > b.sort) return 1;
else if (a.sort < b.sort) return -1;
else return 0;
}
function fnSortArrDesc(a, b) {
if (a.sort < b.sort) return 1;
else if (a.sort > b.sort) return -1;
else return 0;
}
compare1 = rows[0].getElementsByTagName("TD")[0].textContent.toLowerCase();
compare2 = rows[rows.length-1].getElementsByTagName("TD")[0].textContent.toLowerCase();
if(compare1 < compare2){
sortArr = sortArr.sort(fnSortArrDesc);
}else{
sortArr = sortArr.sort(fnSortArrAsc);
}
frag = document.createDocumentFragment();
for (i = 0; i < sortArr.length; i++) {
x = sortArr[i];
frag.appendChild(x.range.extractContents());
}
table.appendChild(frag);
}
完整的工作代码在这里:jsfiddle
答案 0 :(得分:2)
如果要保持表结构几乎相同,这将是完成您要尝试执行的操作的一种方法。
JavaScript的简要说明:
querySelectorAll
中添加到顶级TR中,以获取我们要排序的所有内容的列表。Array.sort
。我使用documentFragment的原因是,与每次将每个范围一次直接添加回表元素相比,它here on MDN节省了DOM回流和渲染的费用。
注意::如果您有表格页脚,则可能想利用tbody
元素,而不是直接处理表格。
function openView(showID) {
$("." + showID).toggle();
}
function sortTable(n) {
var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0;
table = document.getElementById("schInfoTable");
switching = true;
//Set the sorting direction
dir = 1;
var thEl = table.querySelectorAll('th')[n];
if (thEl.classList.contains('asc')) dir = -1;
thEl.classList.toggle('asc');
rows = table.querySelectorAll('tr.sort');
var sortArr = [];
for (i = 0; i < rows.length; i++) {
x = rows[i];
if (i + 1 in rows) y = rows[i + 1].previousElementSibling;
else y = x.parentElement.lastChild;
var obj = {
sort: x.getElementsByTagName("TD")[n].textContent.toLowerCase(),
range: document.createRange()
};
obj.range.setStartBefore(x);
obj.range.setEndAfter(y);
sortArr.push(obj);
}
function fnSortArr(a, b) {
if (a.sort > b.sort) return 1 * dir;
else if (a.sort < b.sort) return -1 * dir;
else return 0;
}
sortArr = sortArr.sort(fnSortArr);
console.log(JSON.stringify(sortArr, null, 2));
frag = document.createDocumentFragment();
for (i = 0; i < sortArr.length; i++) {
x = sortArr[i];
frag.appendChild(x.range.extractContents());
}
table.appendChild(frag);
}
table {
border-spacing: 0;
width: 100%;
border: 1px solid #ddd;
}
th,
td {
text-align: left;
padding: 16px;
}
tr:nth-child(even) {
background-color: #f2f2f2
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table id="schInfoTable">
<thead>
<th onclick="sortTable(0)">Date</th>
<th>Amount</th>
<th>Count</th>
</thead>
<tbody>
<tr class='sort'>
<td><a onclick="openView('2018-11-14')">2018-11-14</a></td>
<td>$23,000.00</td>
<td>12</td>
</tr>
<tr style="display:none; background-color: #cbe7cb;" class="2018-11-14">
<td>Mandy</td>
<td>Designer</td>
<td>View</td>
</tr>
<tr style="display:none; background-color: #cbe7cb;" class="2018-11-14">
<td>Robert</td>
<td>Cook</td>
<td>View</td>
</tr>
<tr class='sort'>
<td><a onclick="openView('2018-11-13')">2018-11-13</a></td>
<td>$13,000.00</td>
<td>8</td>
</tr>
<tr style="display:none; background-color: #cbe7cb;" class="2018-11-13 branches">
<td>James</td>
<td>Driver</td>
<td>View</td>
</tr>
</tbody>
</table>
*编辑:添加排序顺序切换
通常使用的另一种方法是将子行放入子表中。例如,您的子数据如下所示:
<tr><td colspan='3'> <table>...</table> </td></tr>
。
然后,每个顶层行下面都有一个子表行,您总是成对地对行进行排序/移动,而不是处理从零到无穷大的任意数量的子行。
答案 1 :(得分:1)
我对您的问题非常了解,并提出了我的想法。 我希望这个方法能对您有所帮助。
let testData = [{
date: "2018-11-14",
amount: 23000,
count: 12,
people: [{
name: "Mandy",
designation: "Designer",
detail: "View",
},
{
name: "Robert",
designation: "Cook",
detail: "View",
}
]
},
{
date: "2018-11-13",
amount: 13000,
count: 8,
people: [{
name: "James",
designation: "Driver",
detail: "View",
}]
}
]
let testDiv = document.querySelector('#test');
let main = function() {
let mainTable = document.createElement('table');
mainTable.classList.add('table-style');
let mainTbody = document.createElement('tbody');
let mainTheader = document.createElement('tr');
mainTheader.onclick = sort;
let dateHeader = document.createElement('th');
dateHeader.textContent = 'Date';
mainTheader.appendChild(dateHeader);
let amountHeader = document.createElement('th');
mainTheader.appendChild(amountHeader);
amountHeader.textContent = 'Amount';
let countHeader = document.createElement('th');
countHeader.textContent = 'Count';
mainTheader.appendChild(countHeader);
mainTable.appendChild(mainTheader);
let counter = 0;
testData.forEach(object => {
console.log('MAIN', object);
counter++;
let rowEl = document.createElement('tr');
if (counter % 2 === 0) {
rowEl.classList.add('uneven-row');
}
rowEl.onclick = toggle;
rowEl.id = object.date;
let keys = Object.keys(object);
keys.forEach(key => {
console.log(key, ": ", object[key]);
if (key !== 'people') {
let colEl = document.createElement('td');
colEl.textContent = object[key];
rowEl.appendChild(colEl);
} else {
mainTbody.appendChild(rowEl);
let subTableRow = document.createElement('tr');
subTableRow.id = 'detail-' + object.date;
subTableRow.classList.add('hidden');
let subTable = document.createElement('table');
subTable.classList.add('sub-table-style');
subTableRow.appendChild(subTable);
let subTbody = document.createElement('tbody');
object[key].forEach(detail => {
console.log('DETAIL', detail);
let subRowEl = document.createElement('tr');
let detailKeys = Object.keys(detail);
detailKeys.forEach(detailKey => {
console.log(detailKey, ": ", detail[detailKey]);
let subColEl = document.createElement('td');
subColEl.textContent = detail[detailKey];
subRowEl.appendChild(subColEl);
});
subTbody.appendChild(subRowEl);
});
subTable.appendChild(subTbody);
mainTbody.appendChild(subTableRow);
}
});
});
mainTable.appendChild(mainTbody);
testDiv.appendChild(mainTable);
}
let toggle = function() {
let detailEl = document.querySelector('#detail-' + this.id);
console.log('TOGGLE', detailEl);
if (detailEl.classList.contains('hidden')) {
detailEl.classList.toggle('hidden');
console.log('SHOW', detailEl.id);
} else {
detailEl.classList.toggle('hidden');
console.log('HIDE', detailEl);
}
}
let compareAsc = function(a, b) {
console.log('A', a);
console.log('B', b);
if (a.date > b.date) {
return 1;
}
if (a.date < b.date) {
return -1;
}
if (a.date === b.date) {
return 0;
}
}
let compareDesc = function(a, b) {
console.log('A', a);
console.log('B', b);
if (a.date < b.date) {
return 1;
}
if (a.date > b.date) {
return -1;
}
if (a.date === b.date) {
return 0;
}
}
let redraw = function() {
while (testDiv.firstChild) {
testDiv.removeChild(testDiv.firstChild);
}
main();
}
let sort = function() {
console.log('SORT', this.classList)
if (!window.sorted) {
console.log('SORT ASC', this);
testData.sort(compareAsc);
window.sorted = true;
redraw();
} else {
console.log('SORT DESC', this);
testData.sort(compareDesc);
window.sorted = false;
redraw();
}
}
main();
body {
font-family: 'Courier New', Courier, monospace;
}
table {
border: 1px solid #ccc;
border-collapse: collapse;
table-layout: fixed;
width: 600px;
}
.sub-table-style {
border: 0px;
background: lawngreen;
}
td {
width: 150px;
padding: 10px;
margin: 0;
border: 0px;
}
.uneven-row {
background: #ddd;
}
.hidden {
visibility: hidden;
display: none;
height: 0px;
overflow: hidden;
}
<div id="test">
</div>