我正在实施旅行商优化问题,并且使用Java和C程序对该问题进行了编程。该程序将矩阵作为输入并显示最佳路径。
import java.util.InputMismatchException;
import java.util.Scanner;
import java.util.Stack;
public class TSPNearestNeighbour {
private int numberOfNodes;
private Stack<Integer> stack;
public TSPNearestNeighbour() {
stack = new Stack<Integer>();
}
public void tsp(int adjacencyMatrix[][]) {
numberOfNodes = adjacencyMatrix[1].length - 1;
int[] visited = new
int[numberOfNodes + 1];
visited[1] = 1;
stack.push(1);
int element, dst = 0, i;
int min = Integer.MAX_VALUE;
boolean minFlag = false;
System.out.print(1 + "\t");
while (!stack.isEmpty()) {
element = stack.peek();
i = 1;
min = Integer.MAX_VALUE;
while (i <= numberOfNodes) {
if
(adjacencyMatrix[element][i] > 1 && visited[i] == 0) {
if (min > adjacencyMatrix[element][i]) {
min = adjacencyMatrix[element][i];
dst = i;
minFlag = true;
}
}
i++;
}
if (minFlag) {
visited[dst] = 1;
stack.push(dst);
System.out.print(dst + "\t");
minFlag = false;
continue;
}
stack.pop();
}
}
public static void main(String... arg) {
int number_of_nodes;
Scanner scanner = null;
try {
System.out.println("Enter the number of nodes in the graph");
scanner = new Scanner(System.in);
number_of_nodes = scanner.nextInt();
int adjacency_matrix[][] = new int[number_of_nodes + 1][number_of_nodes + 1];
System.out.println("Enter the adjacency matrix");
for (int i = 1; i <= number_of_nodes; i++) {
for (int j = 1; j <= number_of_nodes; j++) {
adjacency_matrix[i][j] = scanner.nextInt();
}
}
for (int i = 1; i <= number_of_nodes; i++) {
for (int j = 1; j <= number_of_nodes; j++) {
if
(adjacency_matrix[i][j] == 1 && adjacency_matrix[j][i] == 0) {
adjacency_matrix[j][i] = 1;
}
}
}
System.out.println("the citys are visited as follows");
TSPNearestNeighbour tspNearestNeighbour = new TSPNearestNeighbour();
tspNearestNeighbour.tsp(adjacency_matrix);
} catch (InputMismatchException inputMismatch) {
System.out.println("Wrong Input format");
}
scanner.close();
}
}
#include<stdio.h>
#include<conio.h>
int a[10][10],visited[10],n,cost=0;
void get()
{
int i,j;
printf("Enter No. of Cities: ");
scanf("%d",&n);
printf("\nEnter Cost Matrix\n");
for(i=0;i < n;i++)
{
printf("\nEnter Elements of Row # : %d\n",i+1);
for( j=0;j < n;j++)
scanf("%d",&a[i][j]);
visited[i]=0;
}
printf("\n\nThe cost list is:\n\n");
for( i=0;i < n;i++)
{
printf("\n\n");
for(j=0;j < n;j++)
printf("\t%d",a[i][j]);
}
}
void mincost(int city)
{
int i,ncity;
visited[city]=1;
printf("%d -->",city+1);
ncity=least(city);
if(ncity==999)
{
ncity=0;
printf("%d",ncity+1);
cost+=a[city][ncity];
return;
}
mincost(ncity);
}
int least(int c)
{
int i,nc=999;
int min=999,kmin;
for(i=0;i < n;i++)
{
if((a[c][i]!=0)&&(visited[i]==0))
if(a[c][i] < min)
{
min=a[i][c]+a[c][i];
kmin=a[c][i];
nc=i;
}
}
if(min!=999)
cost+=kmin;
return nc;
}
void put()
{
printf("\n\nMinimum cost:");
printf("%d",cost);
}
void main()
{
clrscr();
get();
printf("\n\nThe Path is:\n\n");
mincost(0);
put();
getch();
}
这两个程序也可以正常工作。但是我想为此进行案例研究,我需要从网页上为这些矩阵输入信息。那么有没有办法做到这一点?对于Java或c,两者之一都可以。我也知道JSP和Web编程。我只想了解如何获取这些矩阵的输入并将其发送到服务器端。
答案 0 :(得分:0)
对于Java,我使用了Jsp和Servlets。
Index.jsp
C:\Program Files\dotnet\sdk\NuGetFallbackFolder
Servlet Sample.java
<body>
<form action="sample" method="post">
<h1>Travelling Salesman Problem</h1>
<input placeholder="Number of Cities" type="text" name="cities" required="">
<input placeholder="Matrix" type="text" name="matrix" required="">
<button>Submit</button>
</form>
</body>
TSPNearestNeighbour.Java(Java类)
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.InputMismatchException;
import java.util.Scanner;
import java.util.Stack;
import static java.lang.System.out;
public class sample extends HttpServlet {
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String city = request.getParameter("cities");
String numbers = request.getParameter("matrix");
int[] abc=new int[100];
String[] args = new String[2];
args[0] = city;
args[1] = numbers;
abc = TSPNearestNeighbour.main(args); //passing the two arguments to my java class
PrintWriter out = response.getWriter();
for (int i=0;i<=abc.length;i++) {
out.println(abc[i]);
}
}
}