弹出列表视图显示在另一个列表视图的ItemClickListener上

时间:2018-11-17 11:14:43

标签: java android listview popup

我的应用程序内部有一个ListView,当我单击第一个ListView但第二个ListView的每个项目时,我想弹出一个ListView在弹出视图中不会出现。 这是我的整个OnCreate代码:

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    ListView users =  findViewById(R.id.users);
    String[] values = new String[] { "A",
            "B",
            "C",
            "D",
            "E"
    };
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
            android.R.layout.simple_list_item_1, android.R.id.text1, values);
    users.setAdapter(adapter);
    users.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            ListView todo =new ListView(MainActivity.this);
            String[] itemss={"Kick","Make Admin","Mute"};
            ArrayAdapter<String> adapter=new ArrayAdapter<String>(view.getContext(),
                    android.R.layout.simple_list_item_1,android.R.id.text1,itemss);
            todo.setAdapter(adapter);
            todo.setOnItemClickListener(new AdapterView.OnItemClickListener() {
                @Override
                public void onItemClick(AdapterView<?> parent, View view, int
                        position, long id) {
                    ViewGroup vg=(ViewGroup)view;
                    TextView txt=(TextView)vg.findViewById(R.id.txtitem);
                    Toast.makeText(MainActivity.this,txt.getText().toString(),Toast.LENGTH_LONG).show();
                    final CharSequence[] items = {"Delete User","Add User","Ban User"};
                    final ArrayList selectedItems=new ArrayList();
                    AlertDialog.Builder builder = new AlertDialog.Builder(view.getContext());
                    builder.setTitle("Admin accesses");
                    builder.setMultiChoiceItems(items, null, new DialogInterface.OnMultiChoiceClickListener() {
                        @Override
                        public void onClick(DialogInterface dialog, int which, boolean isChecked) {
                            if (isChecked) {
                                selectedItems.add(which);
                            } else if (selectedItems.contains(which)) {
                                selectedItems.remove(Integer.valueOf(which));
                            }
                        }
                    });
                    builder.setPositiveButton("DONE", new DialogInterface.OnClickListener() {
                        @Override
                        public void onClick(DialogInterface dialog, int which) {
                        }
                    });
                    builder.setNegativeButton("CANCEL", new DialogInterface.OnClickListener() {
                        @Override
                        public void onClick(DialogInterface dialog, int which) {
                            dialog.dismiss();
                        }
                    });
                    builder.create();
                    builder.show();
                }
            });
        }
    });
}

如您在代码中所看到的,我想通过单击第二个ListView项目来出现一个弹出复选框,但是首先我必须解决出现第二个ListView的问题 有谁知道我该如何解决?

可以弹出这样的对话框,在另一个ListView的{​​{1}}上显示一个OnItemVlickListener吗?

1 个答案:

答案 0 :(得分:1)

您尚未未在父视图上添加第二个列表视图(活动/您的父布局,例如相对布局/线性布局等)。

  

您需要将待办事项列表添加到父级布局,然后   需要定义布局参数

例如:-

    RelativeLayout relativeLayoutParent = (RelativeLayout) findViewById(R.id.your_relative_layout_parent);
    ListView todo=new ListView(this);
    ViewGroup.LayoutParams layoutParams=new ViewGroup.LayoutParams(ViewGroup.LayoutParams.MATCH_PARENT,ViewGroup.LayoutParams.MATCH_PARENT);
    todo.setLayoutParams(layoutParams);
    relativeLayoutParent.addView(todo);
  

在上面的示例中,我假设您的布局父级为   相对布局。

对于弹出窗口:-

将下面的代码更改为

 builder.create();
 builder.show();

这个

AlertDialog dialog=builder.create();
dialog.show();

它将显示您的多个智利警报对话框。