Question

`enter code here`    cat /etc/oratab|grep -v "^#"|grep -v "N$"|grep -v +ASM|cut -f1 -d: -s
PROD

DEV

this command give output to two database and I want to select  only the PROD part  .thankyou for your help!

scripts $  cat /etc/oratab
#



# This file is used by ORACLE utilities.  It is created by root.sh
# and updated by either Database Configuration Assistant while creating
# a database or ASM Configuration Assistant while creating ASM instance.

# A colon, ':', is used as the field terminator.  A new line terminates
# the entry.  Lines beginning with a pound sign, '#', are comments.
#
# Entries are of the form:
#   $ORACLE_SID:$ORACLE_HOME:<N|Y>:
#
# The first and second fields are the system identifier and home
# directory of the database respectively.  The third filed indicates
# to the dbstart utility that the database should , "Y", or should not,
# "N", be brought up at system boot time.
#
# Multiple entries with the same $ORACLE_SID are not allowed.
#
#

PROD:/u01/app/oracle/product/11.2.0/db_1:Y

DEV:/u01/app/oracle/product/11.2.0/db_1:Y`


    iam trying to automate the database start and stop by writing a shell 
    script and i have two database in server PROD and DEV and the user selects 
    like the script below .
     listdb(){
echo "bases des données dans le serveur   :"
db_list=`cat /etc/oratab|grep -v "^#"|grep -v "N$"|cut -f1 -d: -s`

i=1
for DB in $db_list
do

   echo $i $DB
    i=$(($i+1))
done
read -n1 -p "Select a database to open? [1,2]" doit 
case $doit in  
  1)  startdb() ;; 
  2)  startdb() ;; 
esac
}

所以我想在用户选择其中之一时将数据库的名称作为参数传递，但是我现在想通了（上面的脚本），所以我正在编写打开和停止数据库的功能。是我不经常使用linux，所以它正在学习执行此projet。

Answer 1

您可以使用head：

cat /etc/oratab|grep -v "^#"|grep -v "N$"|grep -v +ASM|cut -f1 -d: -s|head -1

如何在此命令中仅选择“第一”输出？

1 个答案: