我是C的新手,出于我需要的目的,我似乎在指针char上找不到太多东西。这是我的简化代码:
int total, tempX = 0;
printf("Input total people:\n");fflush(stdout);
scanf("%d",&total);
char **nAmer = (char**) malloc(total* sizeof(char));
double *nUmer = (double*) malloc(total* sizeof(double));;
printf("input their name and number:\n");fflush(stdout);
for (tempX = 0;tempX < total; tempX++){
scanf("%20s %lf", *nAmer + tempX, nUmer + tempX); //I know it's (either) this
}
printf("Let me read that back:\n");
for (tempX = 0; tempX < total; tempX++){
printf("Name: %s Number: %lf\n",*(nAmer + tempX), *(nUmer + tempX)); //andor this
}
我不确定在获取用户输入时指针指针char的正确格式是什么。如您所见,我正在尝试获取人们的姓名及其号码的列表。我知道数组,矩阵和类似的东西很容易,但是它只能是一个指针指针。谢谢!
答案 0 :(得分:0)
如果要存储N个字符串(每个字符串最多20个字符),则不仅需要分配用于指向字符串的指针的空间,还需要分配用于存储字符串本身的空间。这是一个示例:
#include <stdlib.h>
#include <stdio.h>
int main(int argc, char ** argv)
{
int total, tempX = 0;
printf("Input total people:\n");fflush(stdout);
scanf("%d",&total);
printf("You entered: %i\n", total);
// note: changed to total*sizeof(char*) since we need to allocate (total) char*'s, not just (total) chars.
char **nAmer = (char**) malloc(total * sizeof(char*));
for (tempX=0; tempX<total; tempX++)
{
nAmer[tempX] = malloc(21); // for each string, allocate space for 20 chars plus 1 for a NUL-terminator byte
}
double *nUmer = (double*) malloc(total* sizeof(double));;
printf("input their name and number:\n");fflush(stdout);
for (tempX = 0; tempX<total; tempX++){
scanf("%20s %lf", nAmer[tempX], &nUmer[tempX]);
}
printf("Let me read that back:\n");
for (tempX = 0; tempX<total; tempX++){
printf("Name: %s Number: %lf\n", nAmer[tempX], nUmer[tempX]);
}
// Finally free all the things we allocated
// This isn't so important in this toy program, since we're about
// to exit anyway, but in a real program you'd need to do this to
// avoid memory leaks
for (tempX=0; tempX<total; tempX++)
{
free(nAmer[tempX]);
}
free(nAmer);
free(nUmer);
}