我有一个简单的注册请求脚本。我的Android Studio应该向URL(php脚本)发送3个字符串,但是PHP无法接收任何数据,或者处理不善。
这是RegisterRequest脚本:(它应该从android studio中接收值,然后使用localhost / ip地址上的POST方法将信息推送到PHP脚本中)
public class RegisterRequest extends StringRequest {
private static final String REGISTER_REQUEST_URL = "http://192.168.*.*:80/phptesting/Register.php";
private Map<String, String> params;
public RegisterRequest(String username, String password,String isAdmin, Response.Listener<String> listener){
super(Method.POST, REGISTER_REQUEST_URL,listener,null);
params = new HashMap<>();
params.put("username",username);
params.put("password",password);
params.put("isAdmin",isAdmin+"");
}
public Map<String, String> getparams() {
return params;
}
}
这是CreateUser脚本。它应该从XML中获取字符串,然后调用RegisterRequest类并移交字符串;
createuser.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
final String username = username1.getText().toString();
final String password = password1.getText().toString();
final String isadmin = isAdmin.getText().toString();
Response.Listener<String> responseListener = new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d("Response Value: ", response);
if (response.equals("success")){
Intent intent = new Intent(CreateUser.this, MainActivity.class);
CreateUser.this.startActivity(intent);
}else{
AlertDialog.Builder builder = new AlertDialog.Builder(CreateUser.this);
builder.setMessage("Register Failed")
.setNegativeButton("Retry",null)
.create()
.show();
}
}
};
RegisterRequest registerRequest = new RegisterRequest(username,password,isadmin,responseListener);
RequestQueue queue = Volley.newRequestQueue(CreateUser.this);
queue.add(registerRequest);
}
});
最后,这是我的PHP脚本,该脚本应接收字符串并将其放入db中;
<?php
$db_host = 'localhost:3306';
$db_user = 'root';
$db_pass = '';
$db_name = 'test';
$con = mysqli_connect($db_host,'user',$db_pass,$db_name);
if($con){
echo "connection successful";
}else{
echo "connection failed";
}
$age = $_POST["isAdmin"];//line 14
$username = $_POST["username"];//line 15
$password = $_POST["password"];//line 16
$statement = mysqli_prepare($con, "INSERT INTO cresidentials (username,password,isAdmin) VALUES (?, ?, ?)");
if(!$statement) { printf("Prepare failed: %s\n", mysqli_error($con)); }
if(!$statement) { return json_encode(['status'=>'failed','message'=>mysqli_error($con)]); }
mysqli_stmt_bind_param($statement, "ssi",$username,$password,$isAdmin);
mysqli_stmt_execute($statement);
if(mysqli_error($con)) { return json_encode(['status'=>'failed','message'=>mysqli_error($con)]); }//line 22
$response = array();
$response["success"] = true;
echo json_encode($response);
?>
我希望我对脚本功能的解释能帮助您调试问题。此外,android studio输出此内容;
注意:未定义的索引:第14行\ Register.php中的isAdmin 注意:未定义的索引:第15行\ Register.php中的用户名 注意:未定义的索引:第16行的\ Register.php中的密码
(是Android Studio不在发送数据吗?还是PHP没有分配接收的内容?PHP是否需要一种仅用于放入数据的方法?)
谢谢您的帮助