Question

因此，我有一个称为ChatClient的类，并与ChatServer类一起用作多聊天加密信使。所以我有一些像下面这样的Swing组件，并在我的ChatClient构造函数中将它们初始化：公共静态ChatClient客户端；

// GUI ELEMENTS
BufferedReader in;
PrintWriter out;
JFrame frame; 
public static JTextArea userText;
JTextArea DisplayMessage;
JLabel connectInfo;
JToggleButton tglbtnConnect;
JToggleButton tglbtnDisconnect;
JLayeredPane layeredPane;
JLayeredPane layeredPane_1;
JRadioButton rdbtnAes;
JRadioButton rdbtnDes;
JRadioButton rdbtnCbs;
JRadioButton rdbtnOfb;
JPanel panel;
JLabel lblServer;
JLabel lblText;
JLabel lblCryptText;
JTextArea encryptedText;
JToggleButton tglbtnNewToggleButton;
JToggleButton tglbtnNewToggleButton_1;

然后我有提供消息的 run（）方法。我的问题是，当我使用如下所示的主要方法时，以便在框架打开时在连接按钮中运行 run（）方法（最初它会询问用户名），并且希望连接后运行该方法按钮：

public static void main(String[] args) throws Exception {
       client = new ChatClient();
       client.frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
       client.frame.setVisible(true);
    }

tglbtnConnect =新的JToggleButton（“ Connect”）; tglbtnConnect.addActionListener（new ActionListener（）{

            @Override
            public void actionPerformed(ActionEvent arg0) {
                try {
                    client.run();
                    connectInfo.setText("Connected");
                } catch (Exception e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }

            }
        });
        tglbtnConnect.setBounds(12, 36, 106, 25);

问题是当我单击connect时，它询问用户名，然后离开gui，这样ı不能使用任何组件。任何帮助或提示表示赞赏。您可以在下面找到我的整个班级：https://pastebin.com/N7Ncz7yk

您可以在下面找到我的运行方法：

private void run() throws Exception {

        // Make connection and initialize streams
        String serverAddress = "localhost";
        Socket socket = new Socket(serverAddress, 9001);
        in = new BufferedReader(new InputStreamReader(
            socket.getInputStream()));
        out = new PrintWriter(socket.getOutputStream(), true);

        // Process all messages from server, according to the protocol.
        while (true) {
            String line = in.readLine();
            if (line.startsWith("SUBMITNAME")) {
                out.println(getName());
            } else if (line.startsWith("NAMEACCEPTED")) {
                userText.setEditable(true);
            } else if (line.startsWith("MESSAGE")) {
                int idx = line.lastIndexOf(">");
                String mssg = line.substring(idx + 1);
                if(rdbtnAes.isSelected() && rdbtnCbs.isSelected()){
                     String key="MZygpewJsCpRrfOr";
                    byte[] encryptionKey = "MZygpewJsCpRrfOr".getBytes();
                    //byte[] plainText = input.getBytes();
                    AES advancedEncryptionStandard = new AES(encryptionKey);
                    byte[] cipherText = advancedEncryptionStandard.encrypt(mssg,key,0);
                    String decryptedCipherText = advancedEncryptionStandard.decrypt(cipherText,key,0);
                    String encrytepdText=new String(cipherText);

                    // APPEND MESSAGE
                     DisplayMessage.append(encrytepdText + "\n" + line.substring(8,idx + 1) + decryptedCipherText + "\n");

                }
                else if(rdbtnAes.isSelected() && rdbtnOfb.isSelected()){
                    String key="MZygpewJsCpRrfOr";
                    byte[] encryptionKey = "MZygpewJsCpRrfOr".getBytes();
                    //byte[] plainText = input.getBytes();
                    AES advancedEncryptionStandard = new AES(encryptionKey);
                    byte[] cipherText = advancedEncryptionStandard.encrypt(mssg,key,1);
                    String decryptedCipherText = advancedEncryptionStandard.decrypt(cipherText,key,1);
                    String encrytepdText=new String(cipherText);

                    // APPEND MESSAGE
                     DisplayMessage.append(encrytepdText + "\n" + line.substring(8,idx + 1) + decryptedCipherText + "\n");

                }
                else if(rdbtnDes.isSelected()&& rdbtnCbs.isSelected()){
                    DES desEncryption=new DES(mssg,0);
                     DisplayMessage.append(desEncryption.encryptedData + "\n" + line.substring(8,idx + 1) + desEncryption.decryptedMessage + "\n");
                }
                else if(rdbtnDes.isSelected() && rdbtnOfb.isSelected()){
                    DES desEncryption=new DES(mssg,1);
                    DisplayMessage.append(desEncryption.encryptedData + "\n" + line.substring(8,idx + 1) + desEncryption.decryptedMessage + "\n");
                }


            }
        }
    }

Answer 1

在您的<amp-audio width="auto" height="50"> <source type="audio/mpeg" src="https://....mp3" [src]="audiosrc"> </amp-audio> <amp-list items="Items" height="315px" layout="fixed-height" src="JSONFILE" id="podcastlist"> <template type="amp-mustache"> <div class="box" on="tap:AMP.setState({ audiosrc : '{{mp3}}' })"> {{name}} </div> </template> </amp-list>方法中，您可以通过编写client.run()而不创建while (true)或break来创建无限循环。因为此方法是从return的UI线程中调用的，所以您的UI卡住了/没有响应“不可用”。

解决方案：创建一个新的ActionListener，该服务器运行服务器侦听代码并从该线程更新UI。 Connect应该仅以Thread开始该线程，然后返回。

运行线程后，Java SWING GUI离开控制台

1 个答案: