Question

我想从JSON中删除JSON元素或整行。

我有以下JSON字符串：

{
   "result":[
       {
           "FirstName": "Test1",
           "LastName":  "User",
       },
       {
           "FirstName": "user",
           "LastName":  "user",
       },
       {
           "FirstName": "Ropbert",
           "LastName":  "Jones",
       },
       {
           "FirstName": "hitesh",
           "LastName":  "prajapti",
       }
   ]
}

Answer 1

var json = { ... };
var key = "foo";
delete json[key]; // Removes json.foo from the dictionary.

您可以使用splice从数组中删除元素。

Answer 2

JSON中没有逗号逗号

更新：如果要从对象中的数组中删除项目，则需要使用array.splice而不删除

var data = {
  "result": [{
    "FirstName": "Test1",
    "LastName": "User"
  }, {
    "FirstName": "user",
    "LastName": "user"
  }]
}
console.log(data.result);
console.log("------------ deleting -------------");
delete data.result[1];
console.log(data.result); // note the "undefined" in the array.


data = {
  "result": [{
    "FirstName": "Test1",
    "LastName": "User"
  }, {
    "FirstName": "user",
    "LastName": "user"
  }]
}

console.log(data.result);
console.log("------------ slicing -------------");
var deletedItem = data.result.splice(1,1);
console.log(data.result); // here no problem with undefined.

Answer 3

您可以尝试删除JSON，如下所示：

var bleh = {first: '1', second: '2', third:'3'}

alert(bleh.first);

delete bleh.first;

alert(bleh.first);

或者，您也可以传入索引以删除属性：

delete bleh[1];

但是，要了解使用删除的一些后果，请查看here

Answer 4

修复JSON中的错误：http://jsonlint.com/
解析JSON（因为您已使用JavaScript标记了问题，请使用json2.js）
Delete来自您创建的对象的属性
将对象字符串化回JSON。

Answer 5

所有的答案都很棒，它也会按照你的要求做，但我相信删除它的最佳方法，以及垃圾收集器的最佳方法（如果你运行node.js）是这样的：

var json = { <your_imported_json_here> };
var key = "somekey";
json[key] = null;
delete json[key];

这样node.js的垃圾收集器就会知道不再需要json['somekey']，并将其删除。

Answer 6

试试以下

var myJSONObject ={"ircEvent": "PRIVMSG", "method": "newURI", "regex": "^http://.*"};
console.log(myJSONObject);
console.log(myJSONObject.ircEvent);
delete myJSONObject.ircEvent 
delete myJSONObject.regex 
console.log(myJSONObject);

Answer 7

如@mplungjan所述，我虽然是对的。然后我马上点击up rate按钮。但通过遵循它，我终于得到了一个错误。

<script>
var data = {"result":[
  {"FirstName":"Test1","LastName":"User","Email":"test@test.com","City":"ahmedabad","State":"sk","Country":"canada","Status":"False","iUserID":"23"},
  {"FirstName":"user","LastName":"user","Email":"u@u.com","City":"ahmedabad","State":"Gujarat","Country":"India","Status":"True","iUserID":"41"},
  {"FirstName":"Ropbert","LastName":"Jones","Email":"Robert@gmail.com","City":"NewYork","State":"gfg","Country":"fgdfgdfg","Status":"True","iUserID":"48"},
  {"FirstName":"hitesh","LastName":"prajapti","Email":"h.prajapati@zzz.com","City":"","State":"","Country":"","Status":"True","iUserID":"78"}
  ]
}
alert(data.result)
delete data.result[3]
alert(data.result)
</script>

删除只是删除数据，但“地点”仍然存在 undefined 。

我这样做了，它就像一个魅力：

data.result.splice(2,1);

含义：删除位置3处的1个项目（因为数组从0开始计算，然后第3个项目计为第2个）

Answer 8

我建议使用<allow-intent href="*" /> <allow-navigation href="*" />方法从JSON对象数组中删除对象。

splice

我使用这个是因为当我使用jQuery(json).each(function (index){ if(json[index].FirstName == "Test1"){ json.splice(index,1); // This will remove the object that first name equals to Test1 return false; // This will stop the execution of jQuery each loop. } });方法时，我会delete

后得到null个对象

Answer 9

如果我们要从数组中删除一个属性，请说“ firstName” 我们可以将map函数与如上所述的delete一起使用

   var result= [
       {
           "FirstName": "Test1",
           "LastName":  "User",
       },
       {
           "FirstName": "user",
           "LastName":  "user",
       },
       {
           "FirstName": "Ropbert",
           "LastName":  "Jones",
       },
       {
           "FirstName": "hitesh",
           "LastName":  "prajapti",
       }
   ]

result.map( el=>{
    delete el["FirstName"]
})
console.log("OUT",result)

Answer 10

对于那些来这里寻求如何根据对象值从JSON数组中删除对象的人

let users = [{"name": "Ben"},{"name": "Tim"},{"name": "Harry"}];

 for (let [i, user] of users.entries()) {
    if (user.name == "Tim") {
        users.splice(i, 1);
    }
 }

用户 Tim 现在已从JSON数组用户中删除。

Answer 11

尝试

json = $.grep(newcurrPayment.paymentTypeInsert, function (el, idx) { return el.FirstName == "Test1" }, true)

删除json元素

11 个答案: