Question

在JSON.net中，如何遍历JObject键的子级的JProperties？

代码：

JObject json = JObject.Parse(jsonstring);
var developments = json["Developments"][0];

//Doesn't work
//Error   CS1929  'JToken' does not contain a definition for 'Properties' and the best extension method overload 'Extensions.Properties(IEnumerable<JObject>)' requires a receiver of type 'IEnumerable<JObject>'
//foreach(JProperty property in development.Properties())
//    Console.WriteLine(property.Name + property.Value);

JSON：

{
  "Developments": {
    "Plot 125": {
      "developer": "XYZ",
      "selection":{
        "Subdivision 1" : "135000",
        "Subdivision 2":  "450000"
      }
    },
    "Plot 126":{
      "developer": "XYZ",
      "selection":{
        "Subdivision 1": "56000",
        "Subdivision 2": "98000",
        "Subdivision 3": "456000"
      }
    }
  }
}

_{与JSON.net 4.0版本6.0.0编译}

Answer 1

所有JToken对象都包含允许您对任何对象进行操作的属性，就好像它是任何有效的json类型一样。

尤其是在json.net中，对象的子代为JProperty。因此，只需获取对象的子代即可。

var query =
    from x in json["Developments"].Children<JProperty>()
    select x.Name;

另一方面，如果已经将其键入为JObject，则可以直接访问属性。

var query =
    from x in ((JObject)json["Developments"]).Properties()
    select x.Name;

如何使用JSON.Net遍历JObject键的JProperties

1 个答案: