我使用此代码来验证用户密码:
$encoderService = $this->container->get('security.password_encoder');
$match = $encoderService->isPasswordValid($user, $request->query->get('password'));
但是即使密码正确也总是返回“ false”
答案 0 :(得分:0)
您以错误的方式使用密码编码器...检查Symfony doc on security
这是一个有关如何使用它的示例。
app / config / security.yml
security:
encoders:
AppBundle\Entity\Security:
algorithm: bcrypt
src / AppBundle / Controller / SecurityController.php
class SecurityController extends Controller {
private $tokenManager;
private $encoder;
public function __construct(CsrfTokenManagerInterface $tokenManager=null, UserPasswordEncoderInterface $encoder) {
$this->tokenManager=$tokenManager;
$this->encoder=$encoder;
}
**[...]**
public function editAction(Security $user) {
if($user->getOldPassword() !== null && $user->getPlainPassword() !== null && $this->encoder->isPasswordValid($user, $user->getOldPassword())) {
$user->setPassword($this->encoder->encodePassword($user, $user->getPlainPassword()));
$em->flush();
}
}
}
表单视图
<form action="{{ form.vars.action }}" method="{{ form.vars.method }}" onsubmit="event.preventDefault(); ajaxSubmit($(this));">
<div class="form-section-title">Change password</div>
<div class="form-col-2">
<div class="input-field">
{{ form_label(form.oldPassword, 'Current password') }}
{{ form_widget(form.oldPassword, { 'attr': {'autocomplete': 'off' }}) }}
</div>
<div class="input-field">
</div>
</div>
<div class="form-col-2">
<div class="input-field">
{{ form_label(form.plainPassword.first, 'New password') }}
{{ form_widget(form.plainPassword.first, { 'attr': {'autocomplete': 'off' }}) }}
</div>
<div class="input-field">
{{ form_label(form.plainPassword.second, 'Repeat new password) }}
{{ form_widget(form.plainPassword.second, { 'attr': {'autocomplete': 'off' }}) }}
</div>
</div>
<input name="{{ form._token.vars.full_name }}" type="hidden" value="{{ form._token.vars.value }}">
<div class="input-field submit-container">
<button class="waves-effect waves-light btn btn-2 close_action">Annuler</button>
<button class="waves-effect waves-light btn btn-1" type="submit">Valider</button>
</div>
</form>
JavaScript提交功能
function ajaxSubmit(node) {
$.ajax({
type: node.attr("method"),
url: node.attr("action"),
enctype: 'multipart/form-data',
data: new FormData(node[0]),
processData: false,
contentType: false,
cache: false
}).done(function(response, status, xhr) {
//Your code here
}).fail(function(request, status, error) {
console.error(request);
console.error(status);
console.error(error);
});
}
旁注:应该很明显,但是您应该在AJAX查询中使用POST
而不是GET
。
首先,因为GET
参数非常清晰,因此更改密码非常危险。
第二,因为一旦您的站点使用HTTPS,您的POST
参数就会被加密。真的很难让任何嗅探内容的人阅读内容。
最后,避免在注释中张贴代码,而是编辑您的问题...;)