嗨,大家需要帮助,我有一个JavaScript代码,用于识别并显示PC时间(基于PC时间)。我有这种情况时,应将数据插入数据库。我使用setinterval,所以当条件为true时,它将转到该页面或php代码(fetch.php代码在下面)。我将所有代码发布在帮助人员的下面。问题是它没有将数据插入数据库。
这是index.php
function startTime() {
var today = new Date();
var h = today.getHours();
var m = today.getMinutes();
var s = today.getSeconds();
m = checkTime(m);
s = checkTime(s);
document.getElementById('txt').innerHTML =
h + ":" + m + ":" + s;
var t = setTimeout(startTime, 500);
if(h == '6' && m == '00')
{
$(document).ready(function() {
setInterval(function () {
$('#auto').load('fetch.php')
},1000);
});
}
}
function checkTime(i) {
if (i < 10) {i = "0" + i};
return i;
}
<!DOCTYPE html>
<html>
<head>
</head>
<body onload="startTime()">
<div id="txt"></div>
<div id="auto"></div>
</body>
</html>
这是fetch.php
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "db";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO tbl(available)
VALUES ('200')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>