Javascript onSelect：函数（日期）alert（）

Question

var holiDays =[[2018,10,23,'New Years Day'],[2018,10,24,'Pongal'],[2018,10,25,'Christmas Day']];

    $('#calendar').datepicker({
                beforeShowDay: setHoliDays,
                onSelect: function (date) {
        alert();       
    }
    });

我可以从setHolidays中的函数alert()的结果中触发title属性吗？

function setHoliDays(date) {
   for (i = 0; i < holiDays.length; i++) {
     if (date.getFullYear() == holiDays[i][0]
          && date.getMonth() == holiDays[i][1] - 1
          && date.getDate() == holiDays[i][2]) {
        return [true, 'holiday', holiDays[i][3]];
     }
   }
  return [true, ''];
}

Answer 1

我想你想要这样的东西。

Program received signal SIGSEGV, Segmentation fault.
0x000000000040072a in addCarinfo (carbase=0x602010, newcar=0x602080)
    at database.c:56
56              tempcar2 = tempcar2->next;
(gdb) bt
#0  0x000000000040072a in addCarinfo (carbase=0x602010, newcar=0x602080)
    at database.c:56
#1  0x0000000000400869 in main () at database.c:98

var holiDays =[[2018,10,23,'New Years Day'],[2018,10,24,'Pongal'],[2018,10,25,'Christmas Day']];

    $('#calendar').datepicker({
                beforeShowDay: setHoliDays,
                onSelect: function (date) {
        getTitle(date)
    }
    });
    
    function setHoliDays(date) {
   for (i = 0; i < holiDays.length; i++) {
     if (date.getFullYear() == holiDays[i][0]
          && date.getMonth() == holiDays[i][1] - 1
          && date.getDate() == holiDays[i][2]) {
        return [true, 'holiday', holiDays[i][3]];
     }
   }
  return [true, ''];
}

function getTitle(date){
var date=new Date(date);
   for (i = 0; i < holiDays.length; i++) {
     if (date.getFullYear() == holiDays[i][0]
          && date.getMonth() == holiDays[i][1] - 1
          && date.getDate() == holiDays[i][2]) {
        alert(holiDays[i][3]);
     }
   }
}

.holiday{
background:red;
}
.holiday a{
    background: red !important;
    color: white !important;
}