Question

我已经检查了我的代码一千次了，但是它从没有弹出，所以我尝试了一个PHP Checker / Tester。它告诉我/home4/phptest/public_html/code.php70(5）中未定义函数test_input（）的调用：eval（）的代码：4堆栈跟踪：＃0 /home4/phptest/public_html/code.php70(5 ）：eval（）＃1 {main}抛出在第4行，这是什么意思？请帮忙！

<?php

        ($_SERVER["REQUEST_METHOD"] == "GET");
        $charName = test_input($_GET["charName"]);
        $charType = test_input($_GET["charType"]);
        $healthTokens = test_input($_GET["healthTokens"]);
        $expTokens = test_input($_GET["expTokens"]);
        $supplyTokens = test_input($_GET["supplyTokens"]);


        $charName = $_POST['charName'];
        $charType = $_POST['charType'];
        $healthTokens = $_POST['healthTokens'];
        $expTokens = $_POST['expTokens'];
        $supplyTokens = $_POST['supplyTokens'];

        if (strtolower($password) == "php123")
        {
            $goldSpent = $healthTokens / 10 + $expTokens / 2 + $supplyTokens / 25;

            print("<h1>You have created $charName the $charType!</h1>");
            print("<p>$charName has $healthTokens health tokens,
                        $expTokens experience tokens, and 
                        $supplyTokens supply tokens.</p>");
            print("<p>$charName has spent $goldSpent gold pieces.</p>");
        }
        else
        {
            print ("<p>Sorry! That password is NOT correct. Please try again</p>");
        }
?>

Answer 1

您调用未在代码中定义的函数：

$ charName = 测试输入（$ _ GET [“ charName”]）;

该功能可以在脚本中未包含的另一个文件中定义。

我找不到我的PHP代码有什么问题。谁能看到错误？

1 个答案: