大家好,我正在使用JPA对项目进行本机查询,但是我不知道如何执行if和else类型的查询 在where子句中,我的?0可以是4个值:10、20、30和40,当?0是10、20、30时,我应该使用CI.QTD <= 当?0为40时,条件应为> =。我怎样才能做到这一点?
将我的代码置于一个条件之后:
SELECT rownum AS id,
x.*
FROM (
SELECT ci.text,
ci.lenght
FROM ci_table CI
WHERE (?0 IS NULL OR ci.qtd <= ?0)
GROUP BY ci.text,
ci.lenght
ORDER BY ci.text) x ,
nativequery = true);
调整后添加查询:
@Query(value =
"SELECT rownum as ID, X.* FROM (SELECT " +
" CI.PARAM1 " +
" CI.PARAM2, " +
" CI.PARAM3, " +
" CI.PARAM4, " +
" CI.PARAM5" +
" FROM " +
" CM_PARAMS CI " +
" WHERE " +
" (?1 is null or CI.PARAM6 = ?1) " +
" AND (?2 is null or CI.PARAM7 = ?2) " +
" AND (?3 is null or CI.PARAM8 = ?3) " +
" AND (?4 is null or CI.PARAM9 = ?4) " +
" AND (?5 is null or CI.PARAM10 = ?5) " +
" AND (?6 is null or CI.PARAM11 = ?6) " +
" AND (?7 is null or CI.PARAM12 = ?7) " +
" AND (?8 is null or CI.PARAM13 = ?8) " +
" AND (CASE WHEN ?9 >30 THEN CI.PARAM14 > 30 " +
" CASE WHEN ?9 <31 THEN CI.PARAM15 <= ?9 END) = 1 " +
" GROUP BY " +
" CI.PARAM1, " +
" CI.PARAM2, " +
" CI.PARAM3, " +
" CI.PARAM4, " +
" CI.PARAM5" +
" ORDER BY " +
" CI.PARAM1 ASC) X " , nativeQuery = true)
答案 0 :(得分:0)
尝试:
SELECT rownum AS id,
x.*
FROM (
SELECT ci.text,
ci.lenght
FROM ci_table CI
WHERE (CASE WHEN ?0 IN (10,20,30) THEN CI.QTD <= ?0
WHEN ?0 = 40 THEN CI.QTD > ?0 END) = 1
GROUP BY ci.text,
ci.lenght
ORDER BY ci.text) x ,
nativequery = true);