var ref = Database.database().reference()
ref.observe(.value, with: { (snapshot: DataSnapshot) in
self.items.removeAll()
for chipItem: DataSnapshot in snapshot.children.allObjects as! [DataSnapshot]{
let chipId: String = chipItem.key
let titles: DataSnapshot = chipItem.childSnapshot(forPath: "titles")
for device in titles.children.allObjects as! [DataSnapshot]{
print("Got device: ", device)
let value: NSDictionary = device.value as! NSDictionary
let deviceTitle: String = value["title"] as! String
let deviceId: String = value["id"] as! String
let deviceState: Bool = chipItem.childSnapshot(forPath: "states/\(deviceId)").value as! Bool
let newDevice = Device()
newDevice.title = deviceTitle
newDevice.chipId = chipId
newDevice.state = deviceState
newDevice.id = deviceId
self.items.append(newDevice)
}
}
self.tableView.reloadData()
我不想绘制所有数据。我想为chipId绘制某些数据(例如123,2)。 chipId将获取引用的数据。
例如:chipId = 123,chipId = 2
注意:创建表时的ChipId参考
答案 0 :(得分:2)
您好,Berk,欢迎来到StackOverflow。为了在不获取所有数据的情况下检索Firebase中的特定项目,您需要更改数据库引用。将引用视为JSON树中的位置。如果需要特定项目,则在创建参考时会在参考中描述该位置。例如。如果我有用户,但只想要一个用户的详细信息,我可以这样做:
let userRef = Database.database().reference().child("Users").child(user.uid)
目前尚不清楚您上面的参考文献也指出了什么,但也许可以添加
.child("123").child("states").child("002")
参考文献将为您提供所需的信息。
编辑:
var ref = Database.database().reference().child("123")
将获得整个123节点,因此您可以删除observe闭包内的迭代器,并使用来访问子节点
let titles = snapshot.childSnapshot(forPath: "titles")
提取数据的编码示例:
private func getData() {
let ref = Database.database().reference().child("akillipriz-stechome").child("123")
ref.observeSingleEvent(of: .value, with: {(_ snapshot: DataSnapshot) -> Void in
for snapshots in snapshot.children.allObjects as! [DataSnapshot] {
guard let dict = snapshots.value as? [String: AnyObject] else { return }
if let states = dict["states"] as? [String: AnyObject] {
print("STATES: \(states)")
} else {
print("States Location is Empty or Nil")
}
if let titles = dict["titles"] as? [String: AnyObject] {
print("TITLES: \(titles)")
} else {
print("States Location is Empty or Nil")
}
}
})
}