Question

我正在努力弄清楚如何完成我在下面概述的内容。

我正在使用有序词典来跟踪每个玩家（键）的分数（值）。 for循环重复的次数与播放器的次数相同。

我的想法是在for循环中更新与x相同索引的键的值，但是我似乎无法弄清楚如何执行它。任何建议表示赞赏，我完全有可能以错误的方式进行处理。

这是我到目前为止所拥有的：

numberOfPlayers = input("\nEnter number of players : ")
print("The number of players has been set to %s \n" % 
(numberOfPlayers))
numberOfPlayersInt = int(numberOfPlayers)
players = collections.OrderedDict()

for index in range(numberOfPlayersInt):
    teamName = input('Team/Player %i, enter a team name :' %(index))
    players[teamName] = 0

    for x in range(numberOfPlayersInt):
        print("Player %d, your question :" % (x + 1)) 
        answer = str(input("\nCorrect ? "))
        if answer.lower() in ['y', 'yes']:
            pass
            #some code here that updates the value for this player.

包含3个条目的字典-a-c看起来像这样：

OrderedDict([('a', 0), ('b', 0), ('c', 0)])

Answer 1

您可以遍历当前词典，并使用它来构建具有新值的替换OrderedDict。通过枚举原始OrderedDict的项目，我们可以获取它们的索引，然后可以将这些vlaues传递给函数以确定它们的新值：

def new_value(index, key, value):
    print("Player %d, your question :" % (index + 1)) 
    answer = str(input("\nCorrect ? "))
    if answer.lower() in ['y', 'yes']:
        return value + 10
    else:
        return value

od = OrderedDict.fromkeys(['player1', 'player2', 'player3'], 0)

od = OrderedDict((k, new_value(i, k, v)) for i, (k, v) in enumerate(od.items()))

您可以使用类似的技术来修改现有字典中的值：

for i, (k, v) in enumerate(od.items()):
    od[k] = new_value(i, k, v)

Answer 2

我相信您想要的只是更新以玩家名称为键的当前玩家的值。我接受了您的代码，并添加了一些描述性的更改，同时使它的样式更具pythonic风格（如蛇形等）：

import collections

num_of_players = int(input("\nEnter number of players : "))
print("The number of players has been set to %s \n" % (num_of_players))

players = collections.OrderedDict()

POINTS_INCREASE = 5 # or any other update you want here

for index in range(num_of_players):
    team_name = raw_input('Team/Player %i, enter a name :' % (index))
    players[team_name] = 0

    print("Lets update player %d ..." % (index))
    answer = str(raw_input("\nCorrect (y, yes) ? "))
    if answer.lower() in ['y', 'yes']:
        players[team_name] += POINTS_INCREASE

print players

如何在python

2 个答案: