Question

我有一个查询生成器，它返回分页数据：

$builder = Example::latest();
        $examples = $builder->with([
                                'activity',
                                'followers',
                                'messages',
                                'assignedTeam',
                                'domain',
                                'history'])
                        ->paginate();

        return response()->json($examples);

该模型有一个访问器isRelativeTo，它是一个布尔值。我想用!isRelativeTo进行过滤。我知道我不能映射它或直接添加一个过滤器，因为它不是一个集合，所以想知道这样做的正确方法是什么？

这是我的访问器逻辑：

public function getIsRelativeAttribute($value)
{
    $user = auth('api')->user();

    return $this->assigned_user_id == $user->id || $this->reported_by == $user->id
        || $user->teams()->where('id', $this->assigned_team_id)->exists();
}

Answer 1

除了访问器，我最终创建了范围。如果有人好奇：

/**
 * Scope the query relative to the authenticated user
 *
 * @param \Illuminate\Database\Eloquent\Builder $query
 * @param \App\User $user
 *
 * @return \Illuminate\Database\Eloquent\Builder
 */
public function scopeRelativeTo($query, User $user)
{
    $teamIDs = $user->teams->pluck('id');

    $query->where('assigned_user_id', $user->id)
        ->orWhere('reported_by', $user->id)
        ->orWhereIn('assigned_team_id', $teamIDs);
}

/**
 * Scope the query NOT relative to the authenticated user
 *
 * @param \Illuminate\Database\Eloquent\Builder $query
 * @param \App\User $user
 *
 * @return \Illuminate\Database\Eloquent\Builder
 */
public function scopeNotRelativeTo($query, User $user)
{
    $teamIDs = $user->teams->pluck('id');

    $query->where(function ($q) {
        $user = auth('api')->user();
        $q->whereNull('assigned_user_id')
          ->orWhere('assigned_user_id', '!=', $user->id);
    })
   ->where('reported_by', '!=', $user->id)
   ->whereNotIn('assigned_team_id', $teamIDs);
}

Laravel 5.7-通过访问者过滤分页的查询构建器？

1 个答案: