Question

我正在尝试取消嵌套一些嵌套字段，并在Google BigQuery中进行子查询。

这很好。

SELECT id, 
custom_field_options
FROM `project.database.ticket_fields`

'custom_field_options'是一个嵌套字段，这给我带来了一些问题。我有“ custom_field_options.id”和“ custom_field_options.name”以及另外两个嵌套字段。

这也很好。

SELECT ticket_fields.id,
ticket_fields.raw_title,
ticket_custom_fields.name AS ticket_custom_fields_name,
ticket_custom_fields.raw_name AS ticket_custom_fields_raw_name,
ticket_custom_fields.value AS ticket_custom_fields_value,
ticket_fields.created_at
FROM `project.database.ticket_fields` AS ticket_fields
LEFT JOIN UNNEST(custom_field_options) AS ticket_custom_fields
GROUP BY 1,2,3,4,5,6

分别运行时，这两个查询都可以正常运行。现在，我试图将第一个查询作为第二个查询的子查询运行，以从该查询中拉回所有ID，然后在此基础上运行下面的查询。

SELECT ticket_fields.id,
ticket_fields.raw_title,
ticket_custom_fields.name AS ticket_custom_fields_name,
ticket_custom_fields.raw_name AS ticket_custom_fields_raw_name,
ticket_custom_fields.value AS ticket_custom_fields_value,
ticket_fields.created_at
FROM `project.database.ticket_fields` AS ticket_fields
LEFT JOIN UNNEST(custom_field_options) AS ticket_custom_fields
  WHERE id IN (SELECT id, 
  custom_field_options
  FROM `project.database.ticket_fields`)
GROUP BY 1,2,3,4,5,6

Answer 1

您可以使id列名合格，以使引用明确：

SELECT ticket_fields.id,
ticket_fields.raw_title,
ticket_custom_fields.name AS ticket_custom_fields_name,
ticket_custom_fields.raw_name AS ticket_custom_fields_raw_name,
ticket_custom_fields.value AS ticket_custom_fields_value,
ticket_fields.created_at
FROM `project.database.ticket_fields` AS ticket_fields
LEFT JOIN UNNEST(custom_field_options) AS ticket_custom_fields
  WHERE ticket_fields.id IN (SELECT id, 
  custom_field_options
  FROM `project.database.ticket_fields`)
GROUP BY 1,2,3,4,5,6

（我假设ticket_fields.id是您要搜索的id）

Google BigQuery中的嵌套字段

1 个答案: