Question

有人可以建议执行此检查的更好方法吗？

即使mydir中没有csv文件，此语句的计算结果也为true，有人可以提供帮助吗？我正在检查是否有（1）一天或更短的文件（2）具有.csv扩展名（3）不在子目录中

    {% extends 'site/layout/layout.html.twig' %}

{% set pageTitle = 'Inscription' %}

{% block title %}{{ pageTitle }}{% endblock %}

{% block body %}
    <div class="container">
        <div class="row" id="informations_personnelles"></div>

        <div class="row">
            <div class="col-xs-12">
                <img src="{{ asset('loader/spinner.gif', 'image_site') }}" alt="Loader" id="spinner" class="img-responsive center-block">
            </div>
        </div>

        <div class="row" id="choix_offre_form">

        </div>

    </div>
{% endblock %}
{% block js %}
    <script>
        $(() => {
            $("#spinner")
                .hide();

            $.ajax({
                type: "POST",
                url: '{{ path('akp_ajax_inscription') }}',
                beforeSend: (() => {
                    $("#informations_personnelles")
                        .html("");
                    $("#spinner")
                        .show();
                }),
                complete: (() => {
                    $("#spinner")
                        .hide();
                }),
                success: ((data) => {
                    $("#informations_personnelles")
                        .html(data);
                }),
            });

            $(document).on("submit", "form#form-informations-personnelles", function (e) {
                e.preventDefault();

                $("#spinner").show();

                console.log('submit');

                $.ajax({
                    type: "POST",
                    url: '{{ path('akp_ajax_inscription') }}',
                    beforeSend: (() => {
                        $("#choix_offre_form").html("");
                        $("#spinner").show();
                    }),
                    complete: (() => {
                        $("#spinner").hide();
                    }),
                    success: ((data) => {
                        $("#choix_offre_form").html(data);
                    }),
                })
                 .done(function () {
                     console.log("OK");
                 })
                 .fail(function () {
                     console.log("Erreur");
                 });
            });
        });
    </script>
{% endblock %}

在调试中，它将此{{ form_start(form, {'action': path('akp_inscription'), 'method': 'POST', 'attr': {'id': 'form-informations-personnelles'}}) }} {{ form_errors(form) }} <div class="col-md-6 col-md-offset-3 col-xs-12"> {{ form_row(form.email) }} </div> <div class="col-md-6 col-md-offset-3 col-xs-12"> {{ form_row(form.username) }} </div> <div class="col-md-6 col-md-offset-3 col-xs-12"> {{ form_row(form.dateNaissance) }} </div> <div class="col-md-6 col-md-offset-3 col-xs-12"> {{ form_row(form.plainPassword) }} </div> <div class="col-md-6 col-md-offset-3 col-xs-12"> {{ form_widget(form.submit) }} </div> {{ form_end(form) }}评估为true；如何解决？这也不起作用

if [[ ! -f $(find "${mydir}" -maxdepth 1 -name "*.csv" -mtime -1) ]]; then

Answer 1

让我们使用包装在函数中的原始代码在这里进行实验：

at_least_one_recent_csv() {
  [[ -f $(find . -maxdepth 1 -name "*.csv" -mtime -1 -print) ]]
}

in_tempdir() {                     # run the command we're passed in a temporary directory
  local tempdir retval
  tempdir=$(mktemp -d "/tmp/test.XXXXXX")
  (cd "$tempdir" && "$@"); retval=$?
  rm -rf "$tempdir"
  return "$retval"
}

with_garbage() {                               # create content find is supposed to ignore
  mkdir -p dir; touch dir/ignored.csv          # subdirectories are ignored
  touch -d "3 days ago" old.csv                # files more than a day old are ignored
  touch not-a-csv.txt;                         # non-*.csv files are ignored
  "$@"
}

with_no_csvs() { "$@"; }                         # our test cases! This one's a noop
with_one_csv() { touch one.csv; "$@"; }          # ...whereas here we create one new CSV 
with_two_csvs() { touch one.csv two.csv; "$@"; } # ...and here we create two.

print_exit_status() {                # run a command, print what it was and its exit status
  local cmd_str retval
  printf -v cmd_str '%q ' "$@"       # generate a string that represents the command
  "$@"; retval=$?                    # actually *run* the command and capture its status
  echo "The exit status of ${cmd_str% } is $retval" >&2  # print command & status
  return "$retval"                   # and then return that exit status to our caller
}

print_exit_status in_tempdir with_garbage with_no_csvs at_least_one_recent_csv
print_exit_status in_tempdir with_garbage with_one_csv at_least_one_recent_csv
print_exit_status in_tempdir with_garbage with_two_csvs at_least_one_recent_csv

...作为输出发出：

The exit status of in_tempdir with_garbage with_no_csvs at_least_one_recent_csv is 1
The exit status of in_tempdir with_garbage with_one_csv at_least_one_recent_csv is 0
The exit status of in_tempdir with_garbage with_two_csvs at_least_one_recent_csv is 1

...因为find有两个结果，所以将它们串联在一起不会产生test -f可以识别为存在的单个文件名。因此，我们在零结果的情况下正确返回false，在单结果的情况下正确返回true，但在两个或更多情况下错误地返回false

但是，如果我们添加了-quit（因此find在一个结果后停止打印）并删除了!，从而定义了at_least_one_recent_csv像这样：

at_least_one_recent_csv() {
  [[ $(find . -maxdepth 1 -name "*.csv" -mtime -1 -print -quit) ]]
}

...输出应该正确：

The exit status of in_tempdir with_garbage with_no_csvs at_least_one_recent_csv is 1
The exit status of in_tempdir with_garbage with_one_csv at_least_one_recent_csv is 0
The exit status of in_tempdir with_garbage with_two_csvs at_least_one_recent_csv is 0

...仅在...实际上存在一个或多个最近创建的CSV时，at_least_one_recent_csv才返回0（真实）值。：）

为什么是 [[ ！ -f $（找到“ $ {mydir}” -maxdepth 1 -name“ * .csv” -mtime -1）]]意外地正确吗？

1 个答案: