Question

认为我们有一个包含大量应用程序的大型项目，这会导致大量查询和变异。对于此类项目，您如何处理graphql代码架构。让我们举个例子。

我有一个名为Accounts的应用程序。它将具有与用户和个人资料有关的查询和变异。我正在使用的文件夹结构是每个应用程序都将具有graphql文件夹，然后将具有schema.py和mutations.py。现在，代码已安排成这样

schema.py

class User(DjangoObjectType):

    class Meta:
        model = CustomUser
        filter_fields = {
            'email': ['exact', ],
        }
        exclude_fields = ('password', 'is_superuser', )
        interfaces = (relay.Node, )


class ProfileNode(DjangoObjectType):

    class Meta:
        model = Profile
        interfaces = (relay.Node, )


class UserQuery(object):

    user = relay.Node.Field(User)
    users = DjangoFilterConnectionField(User)  # resolve_users is not needed now


class ProfileQuery(object):

    profile = relay.Node.Field(ProfileNode)
    profiles = DjangoFilterConnectionField(ProfileNode)


class UserProfile(ObjectType):

    profile = Field(ProfileNode)

    def resolve_profile(self, info, **kwargs):
        if id is not None and info.context.user.is_authenticated:
            profile = Profile.objects.get(user=info.context.user)
            return profile
        return None


class Viewer(ObjectType):

    user = Field(User)

    def resolve_user(self, info, **kwargs):
        if info.context.user.is_authenticated:
            return info.context.user
        return None

mutations.py

class Register(graphene.Mutation):
    """
    Mutation to register a user
    """
    class Arguments:

        first_name = graphene.String(required=True)
        last_name = graphene.String(required=True)
        email = graphene.String(required=True)
        password = graphene.String(required=True)
        password_repeat = graphene.String(required=True)

    success = graphene.Boolean()
    errors = graphene.List(graphene.String)

    def mutate(self, info, first_name, last_name, email, password, password_repeat):
        # console.log('info', info, first_name, last_name, email, password)
        if password == password_repeat:
            try:
                user = CustomUser.objects.create(
                    first_name=first_name,
                    last_name=last_name,
                    email=email,
                    is_active=False
                    )
                print ('user', user)
                user.set_password(password)
                user.save()
                if djoser_settings.get('SEND_ACTIVATION_EMAIL'):
                    send_activation_email(user, info.context)
                return Register(success=bool(user.id))
            # TODO: specify exception
            except Exception:
                errors = ["email", "Email already registered."]
                return Register(success=False, errors=errors)
        errors = ["password", "Passwords don't match."]
        return Register(success=False, errors=errors)

根架构

// just to show the number of mutations just for account apps.
from accounts.graphql.mutations import (
    Activate,
    DeleteAccount,
    Login,
    RefreshToken,
    Register,
    ResetPassword,
    ResetPasswordConfirm,
    )
from accounts.graphql.schema import Viewer, UserProfile


class Mutation(company_mutation.Mutation, graphene.ObjectType):

    activate = Activate.Field()
    debug = graphene.Field(DjangoDebug, name='__debug')


class Query(company_schema.Query, graphene.ObjectType):
    viewer = graphene.Field(Viewer)
    user_profile = graphene.Field(UserProfile)
    debug = graphene.Field(DjangoDebug, name='__debug')

    @staticmethod
    def resolve_viewer(self, info, **kwargs):
        if info.context.user.is_authenticated:
            return info.context.user
        return None

    @staticmethod
    def resolve_user_profile(self, info, **kwargs):
        if info.context.user.is_authenticated and id:
            return info.context.user
        return None


schema = graphene.Schema(query=Query, mutation=Mutation)

您可以看到仅适用于帐户应用的变体。有很多变异，考虑所有应用程序时还会有更多变异。你们这些人如何处理？

Answer 1

我认为仅基于schema.py，queries.py，mutations.py之类的文件的项目组织对大型项目而言非常糟糕。

这就像使用models.py，fields.py，utils.py等文件来组织模型零件一样

特别是，queries.py文件中某个位置定义的GraphQL ObjectType可以被返回或用作突变的输入。

所以我更喜欢一种基于对象及其逻辑关系的结构

schema/
    __init__.py : contains your root schema actual code
    viewer.py : contains the ObjectType Viewer
    user/
        user.py : contains the ObjectType User and UserQuery
        profile.py : contains the ObjectType Profil
        account : contains the account management mutations
    login.py : contains the login / logout mutations
...

注意：您可以使用与查询相同的方式来嵌入突变，以便能够获得类似突变的查询：

mutation {
    account {
        delete(id: 12) {
            status
        }
    }
}

用于可扩展项目的graphql代码组织

1 个答案: