我有以下使用ActiveStorage的模型:
class ProofreadDocument < ApplicationRecord
has_one_attached :file
has_many :paragraphs, dependent: :destroy
scope :with_file_named, -> (filename) {
includes(:paragraphs).joins(file_attachment:
:blob).where("active_storage_blobs.filename = ?", filename).first}
当记录具有匹配的文件名时,它可以很好地工作。但是,当我搜索文件名不存在的记录时,它将返回所有记录。
pry(main)> ProofreadDocument.with_file_named("M6").count
ProofreadDocument Load (6.9ms) SELECT "proofread_documents".* FROM
"proofread_documents" INNER JOIN "active_storage_attachments" ON
"active_storage_attachments"."record_id" = "proofread_documents"."id" AND
"active_storage_attachments"."record_type" = $1 AND
"active_storage_attachments"."name" = $2 INNER JOIN "active_storage_blobs"
ON "active_storage_blobs"."id" = "active_storage_attachments"."blob_id"
WHERE (active_storage_blobs.filename = 'M6') ORDER BY
"proofread_documents"."id" ASC LIMIT $3 [["record_type",
"ProofreadDocument"], ["name", "file"], ["LIMIT", 1]]
(0.5ms) SELECT COUNT(*) FROM "proofread_documents"
=> 576
如何解决此问题,以便在给定文件名没有记录的情况下返回0条记录?
答案 0 :(得分:0)
您的范围返回一个记录对象或nil
。对于the docs for the scope
macro,范围应返回ActiveRecord::Relation
;当它返回nil
时(就像没有二进制文件给定文件名时一样),它等效于all
(加了强调):
添加用于检索和查询对象的类方法。该方法旨在返回ActiveRecord :: Relation对象,该对象可与其他作用域组成。 如果返回
nil
或false
,则返回all
范围。
通过删除对first
的调用来修改范围以返回关系:
scope :with_file_named, -> (filename) do
includes(:paragraphs).joins(file_attachment: :blob).where("active_storage_blobs.filename = ?", filename)
end