这是用于读取.txt文件并将其用:
分割并打印出结果的代码。但是我陷入了while循环中。这是我的代码。
#include <iostream>
#include <fstream>
#include <string>
#include <cstring>
using namespace std;
string* split(const string& str, const string& delim) {
string* string_list = new string[10];
int idx = 0;
char *token = strtok(const_cast<char*>(str.c_str()), delim.c_str());
while (token != NULL) {
string_list[idx] = token;
token = strtok(NULL, delim.c_str());
++idx;
}
return string_list;
}
struct Item {
string name;
string age;
string id;
string subject[10];
};
struct Item* create_item() {
struct Item* pitem = new Item;
return pitem;
};
void insert_item(struct Item *prev_item, struct Item *item) {
item = (prev_item + 5);
}
int main() {
string student, student2;
string *string_list, *subject, *string_list2, *subject2;
struct Item* pstudent, *pstudent2;
ifstream fin;
fin.open("input.txt");
fin >> student;
while (student != "\n") {
string_list = split(student, ":");
pstudent = create_item();
pstudent->name = *string_list;
pstudent->age = *(string_list + 1);
pstudent->id = *(string_list + 2);
subject = split(*(string_list + 3), ",");
for (int i = 0; i < 10; i++) {
if (*(subject + i) != "") {
pstudent->subject[i] = *(subject + i);
}
}
cout << *(string_list+1) << endl;
fin >> student2;
string_list = split(student2, ":");
pstudent2 = create_item();
insert_item(pstudent, pstudent2);
pstudent2->name = *(string_list);
pstudent2->age = *(string_list + 1);
pstudent2->id = *(string_list + 2);
subject2 = split(*(string_list + 3), ",");
for (int i = 0; i < 10; i++) {
if (*(subject2 + i) != "") {
pstudent2->subject[i] = *(subject2 + i);
}
}
}
cout << pstudent2->name << endl;
fin.close();
return 0;
}
我仍在处理此代码,但是main()中的while循环不会停止。我希望在input.txt文件输入是换行符时停止它。
input.txt是
Mary:20:287:Math,Algorithm \ n 汤姆:21:202:数学,英语\ n 嘻:20:256:数学
提前谢谢!
答案 0 :(得分:0)
不要试图在循环体中处理多个学生。
使用现有的集合类型,而不是尝试编写链表类型。
getColumns