Question

我是javascript新手。你能帮我从这个数组做吗：

[ [ '00011111', 'ADMIN' ],
  [ '00033333', 'ACTIVITY' ],
  [ '00022222', 'SUPPORT' ],
  [ '00011111', 'MEMBER' ],
  [ '00022222', 'MEMBER' ],
  [ '00033333', 'MEMBER' ] ]

这个：

[ [ '00011111', 'ADMIN', 'MEMBER' ],
  [ '00033333', 'ACTIVITY', 'MEMBER' ],
  [ '00022222', 'SUPPORT', 'MEMBER' ] ]

先谢谢您。如果您可以建议几个变体，那就太好了：）

Answer 1

您可以通过检查公用键是否在结果数组中来缩小数组，然后将其推入值或将新数组推入结果集。

var array = [['00011111', 'ADMIN'], ['00033333', 'ACTIVITY'], ['00022222', 'SUPPORT'], ['00011111', 'MEMBER'], ['00022222', 'MEMBER'], ['00033333', 'MEMBER']],
    result = array.reduce((r, [k, v]) => {
        var temp = r.find(([key]) => k === key);
        if (temp) {
            temp.push(v);
        } else {
            r.push([k, v]);
        }
        return r;
    }, []);
    
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

注意：具有for循环的简单策略

@Bean
public OAuth2RestOperations sampleROPCRestTemplate() {
    return new OAuth2RestTemplate(sampleforcePasswordResourceDetails(), new DefaultOAuth2ClientContext(new DefaultAccessTokenRequest()));
}

@Bean
protected OAuth2ProtectedResourceDetails sampleforcePasswordResourceDetails() {
    ResourceOwnerPasswordResourceDetails resource = new ResourceOwnerPasswordResourceDetails();
    resource.setAccessTokenUri(tokenUrl);
    resource.setClientId(clientId);
    resource.setClientSecret(clientSecret);
    resource.setUsername(username);
    resource.setPassword(password);
    resource.setClientAuthenticationScheme(AuthenticationScheme.form);
    resource.setGrantType("password");
    return resource;
}

Answer 3

使用ID和列表时，我建议使用一个对象。

通过这种方式，我们可以将id用作索引，这使得处理数据更加容易：

//Original data
var originalData = [
  ['00011111', 'ADMIN'],
  ['00033333', 'ACTIVITY'],
  ['00022222', 'SUPPORT'],
  ['00011111', 'MEMBER'],
  ['00022222', 'MEMBER'],
  ['00033333', 'MEMBER']
];
//The new variable, which is in the form of an object
var newData = {};
//Loop through original data
originalData.forEach(function(dataPoints) {
  //If first time we encounter this id, create an array on newdata using the first element as key
  if (newData[dataPoints[0]] === void 0) {
    newData[dataPoints[0]] = [];
  }
  //Push secondary elements to our object, using the first element as key
  for (var index = 1; index < dataPoints.length; index++) {
    var dataPoint = dataPoints[index];
    newData[dataPoints[0]].push(dataPoint);
  }
});
//Output our new data object
console.log(newData);
//get data by id
console.log(newData["00033333"]);

Answer 4

route.post('/pay',async(req,res)=>{

  try {
    const link = 'https://app.sandbox.midtrans.com/snap/v1/transactions'

    const obj = {"transaction_details": {"order_id":"order-12","gross_amount": 5000}}

    const data = await axios.post(link,obj,
      { 
        headers : {
          "Accept": "application/json",
          "Content-Type": "application/json",
          Authorization: `Basic ${Base64.encode('*******')}`  
        }
      })


      const koin = data.data.token
      transaction.create({
        order_id : obj.transaction_details.order_id,
        gross_amount : obj.transaction_details.gross_amount,
        token : koin
      })
      console.log(data.data.token)

      res.json(data)
  } catch (error) {
    console.log(error)
  }

})

此方法首先将原始列表缩小为以下形式的对象：

const input = [ [ '00011111', 'ADMIN' ],
  [ '00033333', 'ACTIVITY' ],
  [ '00022222', 'SUPPORT' ],
  [ '00011111', 'MEMBER' ],
  [ '00022222', 'MEMBER' ],
  [ '00033333', 'MEMBER' ] ]

const expected = [ [ '00011111', 'ADMIN', 'MEMBER' ],
  [ '00033333', 'ACTIVITY', 'MEMBER' ],
  [ '00022222', 'SUPPORT', 'MEMBER' ] ]
  
const collate = xs => Object.entries(xs.reduce(
  (a, [id, type]) => ({
    ...a,
    [id]: [...(a[id] || []), type ]
  })
, {})).map(
  ([id, types]) => [id, ...types]
)

console.log(collate(input))

然后遍历该对象条目，将每个条目折叠为一个平面数组。

JavaScript数组填充（一对多）

4 个答案: