我有一张表,我想从中获取两个字段,其中一个是JSONB,并将JSONB值添加到新列中。
SELECT ID, ATTRIBS from EMPLOYEE;
这将向我返回如下输出。
id | attribs
------------------------------------------------------------------------------------
EM001 | {"Education": "C.A.", "Contact No": "6655448822", "Relative Name": "Ganga"}
EM002 | {"Education": "M.E.", "Contact No": "6542349992", "Relative Name": "Yamuna"}
我希望得到如下输出
id | Education | Contact No | Relative Name
-----------------------------------------------
EM001 | C.A. | 6655448822 | Ganga
EM002 | M.E. | 6542349992 | Yamuna
有人建议我该怎么做吗?
答案 0 :(得分:1)
使用->>
运算符根据键提取值:
select id,
attribs ->> 'Education' as education,
attribs ->> 'Contact No' as "Contact No",
attribs ->> 'Relative Name' as "Relative Name"
from the_table