ScalaTest AsyncFunSuiteLike多个断言

时间:2018-10-04 20:59:21

标签: scala scalatest

我正在重写用于测试以String响应的Akka演员的测试,现在,我们使用的是返回Future[String]的函数。因此,请使用AsyncFunSuiteLike重写测试。

目前,我正在寻找一种必须断言多个Future的测试,但是我似乎并不了解如何使用AsyncFunSuiteLike实现它。

我的测试如下:

test("Error responses") {

    NanoHTTPD.Response.Status.values().filter(status => status.getRequestStatus >= 400).map {
      status => {
        val statusCode = status.getRequestStatus
        httpService.setStatusCode(status)
        val responseBody = s"Request failed with status $status"
        httpService.setResponseContent(responseBody)
        val errorMessage = s"Error response (${status.getRequestStatus}): $responseBody"

        myobject.request("123456").map {
          resp => assert(resp === "....")
        }
      }
    }

}

但是我遇到了一个错误type missmatch. Expected: Future[Assertion] actual: List[Future[scalatest.Assertion]]

关于如何在单个测试中实现多个断言的任何想法吗?

1 个答案:

答案 0 :(得分:2)

ScalaTest asynchronous testing期望测试主体返回Future[Assertion]。现在您的测试正文返回List[Future[Assertion]]],因为

NanoHTTPD.Response.Status.values() ... // Returns List
  ...
    myobject.request("123456").map(resp => assert(resp === "....")} // Returns Future[Assertion]
  ...
}

我们可以使用

List[Future[T]]转换为Future[List[T]]
Future.sequence(listOfFutures)

,并且我们可以使用{p>将List[Assertion]转换为Assertion

assert(listOfAssertions.forall(_ == Succeeded))

将其组合在一起

Future.sequence {
  NanoHTTPD.Response.Status.values().filter(status => status.getRequestStatus >= 400).map {
    status => {
      val statusCode = status.getRequestStatus
      httpService.setStatusCode(status)
      val responseBody = s"Request failed with status $status"
      httpService.setResponseContent(responseBody)
      val errorMessage = s"Error response (${status.getRequestStatus}): $responseBody"

      myobject.request("123456").map {
        resp => assert(resp === "....")
      }
    }
  }
}.map(listOfAssertions => assert(listOfAssertions.forall(_ == Succeeded)))