如何删除元组列表中的重叠元素？

Question

我有一个元组列表

[('one','two','three'),('four','five','six'),('seven','eight','nine')]

和列表

['three','five','nine']

我要做的是删除与

重叠的元组的任何元素

第二个列表，这样我就可以了

[('one','two'),('four','six'),('seven','eight')]

有一种简单的方法吗？

Answer 1

listoflists = [('one','two','three'),('four','five','six'),('seven','eight','nine')]
toremove = ['three','five','nine']

outcome = [tuple(item for item in list if item not in toremove) for list in listoflists]

Answer 2

创建一个新的元组列表

a=[('one','two','three'),('four','five','six'),('seven','eight','nine')]
b=['three','five','nine']
[set(i).difference(b) for i in a] # if you do not care about the order inside the tuple