使用Python在新的.json文件中打印json的每一行

时间:2018-10-03 18:24:16

标签: python json loops

我有一个json文件;我需要从内容中删除id键,可以使用我的代码进行操作。

现在,我想将json文件的每一行打印到一个新文件中,并将json中的文件名用作文件名。

我的json文件例如:

{"categories":["Test"],"indications":[{"@class":"=indication.BuildLogIndication","pattern":".*TypeError .*"},{"@class":"model.indication.BuildLogIndication","pattern":".*LoadError .*"}],"modifications":[{"time":{"$date":"2015-10-08T20:01:54.075Z"}},{"user":"user1","time":{"$date":"2015-03-04T18:38:58.123Z"}},{"user":"user2","time":{"$date":"2014-11-13T01:54:13.906Z"}},{"time":{"$date":"2014-09-02T18:48:05.000Z"}}],"lastOccurred":{"$date":"2017-01-25T20:05:17.180Z"}}
{"pattern":".*look for this string.*"}],"modifications":[{"time":{"$date":"2014-09-02T18:52:20.000Z"}}],"lastOccurred":{"$date":"2014-11-04T00:43:32.945Z"},"_removed":{"timestamp":{"$date":"2014-11-13T01:52:44.346Z"},"by":"user3"},"active":false}

删除ID的代码:

import json
import sys
import re
import fileinput

infile = "failure.json"
outfile = "failure1.json"

fin = open(infile)
fout = open(outfile, "w+")
for line in fin:
    for word in line:
        line = re.sub("\"_id.*?},","", line)
    fout.write(line)
    file.write("%d\n" % n)
fin.close()
fout.close()

3 个答案:

答案 0 :(得分:1)

要删除,您可以使用以下内容:

import json
import sys
import re
import fileinput

with open('failure.json') as data_file:
    data = json.load(data_file)
    del data['_id']


with open('failure2.json', 'w') as data_file:
    data = json.dump(data, data_file)

并且为了创建具有id值的文件,只需解析data对象和id节点的值

答案 1 :(得分:0)

您的示例输入在每行上显示一个json对象。

因此,我的解决方案读取每一行并将其转换为python dict(使用json.loads()),从dict中删除所需的密钥(使用{{3} }(如果没有该密钥,则会无提示地失败),然后将其转换回字符串(使用dict.pop()),然后将其写入新文件。

import json

infile = "failure.json"
outfile = "failure1.json"
key = '_id'

with open(infile) as f_read:
    with open(outfile, 'w') as f_write:
        for line in f_read:
            line = line.strip()
            if len(line) > 0:
                try:
                    elem = json.loads(line)
                    elem.pop(key, None)
                    f_write.write('{}\n'.format(json.dumps(elem)))
                except json.JSONDecodeError:
                    pass

编辑:根据OP的评论,显然每一行json都应放入一个单独的新文件中。例如,可以这样做:

import json

infile = "failure.json"
key_to_remove = '_id'

with open(infile) as f_read:
    for line in f_read:
        line = line.strip()
        if len(line) > 0:
            try:
                elem = json.loads(line)
                elem.pop(key_to_remove, None)

                outfile = '{}.json'.format(elem['name'])      # this may raise KeyError
                with open(outfile, 'w') as f_write:
                    f_write.write('{}\n'.format(json.dumps(elem)))
            except json.JSONDecodeError:
                pass

答案 2 :(得分:0)

您已经导入了json程序包,但没有使用它。您应该,这很棒。

从文件中获取字符串,然后使用json.loads()将字符串加载到json对象中。从那里,您可以使用for key in json_object获取json对象的每个元素。