Question

我试图在Active MQ（版本5.15.0）中创建使用者级别的超时。考虑到一条消息是由消费者选择的，但无法确认，因此在这种情况下，我希望消费者超时，以便其他收听经纪人的消费者可以选择相同的消息。

我的生产者代码，我在其中设置了两个消费者监听器：

public class JmsMessageListenerAckExample {
  public static void main(String[] args) throws URISyntaxException, Exception {
    Connection connection = null;
    try {
      // Producer
      ConnectionFactory factory = createActiveMQConnectionFactory();
      connection = factory.createConnection();
      Session session = connection.createSession(false,
          Session.CLIENT_ACKNOWLEDGE);
      Queue queue = session.createQueue("customerQueue");
      String payload = "Important Task";
      Message msg = session.createTextMessage(payload);
      MessageProducer producer = session.createProducer(queue);

      System.out.println("Sending text '" + payload + "'");
      producer.send(msg);

      // Consumer
      MessageConsumer consumer1 = session.createConsumer(queue);
      consumer1.setMessageListener(
          new AckMessageListener(false, "consumer1"));
      Thread.sleep(1000);
      System.out.println("Creating new message listener to acknowledge");
      producer.send(msg);
      MessageConsumer consumer2 = session.createConsumer(queue);
      consumer2.setMessageListener(
          new AckMessageListener(true, "consumer2"));
      connection.start();

      Thread.sleep(3000);
      session.close();
    } finally {
      if (connection != null) {
        connection.close();
      }
    }
  }

  private static ActiveMQConnectionFactory createActiveMQConnectionFactory() {
    // Create a connection factory.
    final ActiveMQConnectionFactory connectionFactory =
        new ActiveMQConnectionFactory("tcp://localhost:61616");

    // Pass the username and password.
    connectionFactory.setUserName("user");
    connectionFactory.setPassword("user");
    return connectionFactory;
  }
}

这是我的消费者听众：

public class AckMessageListener implements MessageListener {
  private boolean acknowledge;
  private String consumerName;

  public AckMessageListener(boolean acknowledge, String consumerName) {
    this.acknowledge = acknowledge;
    this.consumerName = consumerName;
  }

  public void onMessage(Message message) {
    boolean terminate = !acknowledge;
    try {

      System.out.println("ConsumerName="+consumerName+", Acknowledge="+acknowledge);
      if (acknowledge) {
        try {
          message.acknowledge();
        } catch (JMSException e1) {
          e1.printStackTrace();
        }
      }

      System.out.println(message);
    } catch (InterruptedException e) {
      e.printStackTrace();
    } finally {
      if (terminate) {
        Thread.currentThread().interrupt();
      }
    }
  }
}

我想模拟一种方式，consumer1听消息但不确认，以至于超时我正在尝试释放线程，我希望我的consumer2能够接受并给出对消息的确认，以便消息在代理中从“已排队的消息”状态转移到“已排队的消息”状态，但是我的consumer2无法接收任何消息事件。

我在做错什么吗？如何通过Active MQ实现使用者级别的超时？

Answer 1

一种解决方法是使用事务（http://activemq.apache.org/how-do-transactions-work.html）。您可以在调用成功时调用commit（），在失败时调用rollback（），或者如果在调用commit（）之前关闭了会话，则将发生重新传递（http://activemq.apache.org/message-redelivery-and-dlq-handling.html）。

ActiveMQ消费者级别超时

1 个答案: