我正在尝试使用纯JPA保存实体,并且保存时未返回Postgres UUID
字段。默认情况下,使用UUID
自动生成public.uuid_generate_v1mc()
字段。我将postgres用作数据库,由于某种原因,在jpa中保存时创建的默认值不会返回。我尝试添加一个@Generated
字段并将其设置为auto,但这没有任何作用。
我做错什么了吗?
数据库创建语句
CREATE TABLE usermgmt.test
(
id SERIAL PRIMARY KEY,
active boolean NOT NULL DEFAULT false,
created timestamp without time zone NOT NULL DEFAULT now(),
updated timestamp without time zone NOT NULL DEFAULT now(),
description character varying,
name character varying NOT NULL,
external_id bigint UNIQUE ,
uuid uuid DEFAULT public.uuid_generate_v1mc(),
alias character varying NOT NULL UNIQUE,
code character varying NOT NULL UNIQUE
);
实体
@SuppressWarnings("serial")
@Entity(name = "managementTest")
@Cacheable
@Table(schema = "usermgmt", name = "test")
public class Test extends BaseEntity implements Serializable {
@Id
@GeneratedValue(strategy= GenerationType.IDENTITY)
private Long id;
@Column(nullable = false)
private String name;
@Column(nullable = false)
private String description;
@Column(nullable = false, insertable = false, updatable = false)
private UUID uuid;
@Column(nullable = false, unique = true)
private String alias;
@Column(nullable = false, unique = true)
private String code;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
/**
* @return the name
*/
public String getName() {
return name;
}
/**
* @param name the name to set
*/
public void setName(String name) {
this.name = name;
}
/**
* @return
*/
public String getDescription() {
return description;
}
/**
* @param description
*/
public void setDescription(String description) {
this.description = description;
}
/**
* @return the uuid
*/
public UUID getUuid() {
return uuid;
}
public void setUuid(UUID uuid) {
this.uuid = uuid;
}
public String getAlias() {
return alias;
}
public void setAlias(String alias) {
this.alias = alias;
}
public String getCode() {
return code;
}
public void setCode(String code) {
this.code = code;
}
}
基础实体
@MappedSuperclass
public abstract class BaseEntity {
private LocalDateTime created;
private LocalDateTime updated;
@NotNull
private Boolean active;
public BaseEntity() {
this.active = Boolean.TRUE;
}
@PrePersist
@PreUpdate
void setDates() {
if (this.created == null) {
this.created = LocalDateTime.now();
}
this.updated = LocalDateTime.now();
}
public Boolean getActive() {
return this.active;
}
public void setActive(Boolean active) {
this.active = active;
}
public LocalDateTime getCreated() {
return this.created;
}
public LocalDateTime getUpdated() {
return this.updated;
}
public void setUpdated(LocalDateTime updated) {
this.updated = updated;
}
public void touch() {
this.updated = LocalDateTime.now();
}
}
Crud
@Repository("managementTestCrudRepository")
public interface TestCrudRepository extends JpaRepository<Test, Long> {
Test findByCode(String code);
Test findByUuid(UUID uuid);
Test findByAlias(String alias);
List<Test> findByActive(Boolean active);
}
这是我用来保存实体的方法
@PutMapping
public Test putByJson(@RequestBody String json) {
return testCrudRepository.save(new Gson().fromJson(json, Test.class));
}
邮递员返回的对象
{
"created": {
"month": "OCTOBER",
"year": 2018,
"dayOfYear": 275,
"hour": 11,
"minute": 9,
"nano": 325000000,
"second": 52,
"dayOfMonth": 2,
"dayOfWeek": "TUESDAY",
"monthValue": 10,
"chronology": {
"id": "ISO",
"calendarType": "iso8601"
}
},
"updated": {
"month": "OCTOBER",
"year": 2018,
"dayOfYear": 275,
"hour": 11,
"minute": 9,
"nano": 329000000,
"second": 52,
"dayOfMonth": 2,
"dayOfWeek": "TUESDAY",
"monthValue": 10,
"chronology": {
"id": "ISO",
"calendarType": "iso8601"
}
},
"active": true,
"id": 2,
"externalId": null,
"name": "test1",
"description": "test1",
"uuid": null,
"alias": "test1",
"code": "test1"
}
答案 0 :(得分:2)
您需要在数据库将生成的字段上添加@Generated
批注。
@Generated(GenerationTime.ALWAYS)
private UUID uuid;
您需要找到一种方法来告知JPA提供程序有关(1)在数据库端生成的字段以及(2)何时获取它们的信息。
对于此类属性,有一个名为@Generated
的注释,它提供了两个选项:
GenerationTime.INSERT
)上获取生成的属性; GenerationTime.ALWAYS
)上都获取生成的属性。要检索所需的@Generated
值,Hibernate(Spring将其用作默认的JPA提供程序)将执行附加的SELECT
语句。
我不知道您打算将PUT
端点用于(创建/更新/覆盖资源 1 ),但是我会选择@Generated(ALWAYS)
,因为,使用@Generated(INSERT)
,您将在更新/合并时获得null
。
我觉得这段视频非常有启发性,而且很讲究。
答案 1 :(得分:1)
所以我发现您必须使用注释@Generated(GenerationTime.INSERT)
我实际上是在使用@GeneratedValue,为此我尝试了所有不同的值,但没有一个起作用。最后,在使用@Generated(GenerationTime.INSERT)后,它可以正常工作。