Question

这里的代码是，我先读取文件配置，然后再将目录传递到称为ednotes_extractor.get_ednotes（）的方法中

 from preprocessing import ednotes_extractor

    csf_config_txt = open("..\CFS_Config.txt", "r")

    file_list = []
    root_dir = ""
    edn_txt = ""
    pcr_txt = ""

    for line in csf_config_txt:
        file_list.append(line)

    if "Folder Path = " in file_list[0]:
        root_dir = str(file_list[0])
        root_dir = root_dir.replace("Folder Path = ", "")
        root_dir = root_dir.replace("\n", "")

    if "ED Notes = " in file_list[1]:
        root_dir = str(file_list[1])
        root_dir = root_dir.replace("ED Notes = ", "")
        root_dir = root_dir.replace("\n", "")

    if "Patient Care Record = " in file_list[2]:
        root_dir = str(file_list[2])
        root_dir = root_dir.replace("Patient Care Record = ", "")
        root_dir = root_dir.replace("\n", "")

    print(file_list[2])

    def convert_txt(choices):
        if(choices == 1):
            #I would like to pass a directory in this method called theednotes_extractor 
            ednotes_extractor.get_ednotes(str2=file_list[1])
        elif(choices==2):
            print("Hi")

Answer 1

也许这会有所帮助

arr1 = [1,2,3]
arr2 = [4,5,6]

只需添加两个不带[]的数组

arr3 = arr1 + arr2

以您的情况

x = []
for i in range(0, len(arr_cat)):
    x += arr_cat[i]
print(len(x))

以上内容就足够了。

Answer 2

列表理解会做到这一点。它将解压缩列表列表并将其放入新列表中。

flat_list = [item for sublist in arr_cat for item in sublist]
arr_cat = flat_list

Answer 3

尝试一下：

from itertools import chain

new_list = list(chain(*arr_cat))

如何将文件目录作为方法参数传递？

3 个答案: