计时器重置时,重置QLCD编号上的输出

时间:2018-09-26 11:05:42

标签: python-3.x user-interface pyqt5 qlcdnumber

我目前有一个代码,该代码通过按钮启动倒数计时器,我想要的是每当用户按下按钮时,计时器从120开始重新启动,目前它仅继续运行且未重置。

我的代码的相关部分如下:

class ControlMainWindow(QtWidgets.QMainWindow):
    def __init__(self,parent=None):
        super(ControlMainWindow,self).__init__(parent)
        self.ui = Ui_MainWindow()
        self.ui.setupUi(self)

        self.ui.OuterSwitch.clicked.connect(self.OuterControl)
        self.ui.InnerSwitch.clicked.connect(self.InnerControl)

        self.current_timer = None
        self.LCD_timer = None
        self.i = 121

    def LCDtimer(self):
        if self.LCD_timer:
            self.LCD_timer.stop()
            self.LCD_timer.deleteLater()
        self.LCD_timer = QtCore.QTimer()
        self.LCD_timer.start(0)
        self.LCD_timer.timeout.connect(self.updateLCDNumber)

    def starttimer(self):
        if self.current_timer:
            self.current_timer.stop()
            self.current_timer.deleteLater()
        self.current_timer=QtCore.QTimer()
        self.current_timer.setSingleShot(True)
        self.current_timer.start(120000)
        self.current_timer.timeout.connect(self.InnerSwitchOn)


    def updateLCDNumber(self):
        if self.i !=0:
            QtTest.QTest.qWait(1000)
            self.i = self.i-1
            self.ui.Timer.display(self.i)

    def InnerSwitchOn(self):   
        self.ui.InnerSwitch.setEnabled(True)

    def OuterControl(self):
        if GPIO.input(Inner)==0: #InnerDoorOpen
            return GPIO.output(Outer,GPIO.HIGH),print("Please Close Inner Door")
        elif GPIO.input(Outer) ==1: #Outer Door Close
            self.ui.OuterSwitch.setText(QtWidgets.QApplication.translate("MainWindow", "Close Outer Door",None))
            QtWidgets.QApplication.processEvents()
            return GPIO.output(Outer,GPIO.LOW) #Open Outer Door
        elif GPIO.input(Outer) == 0: #OuterDoor Open
            self.ui.InnerSwitch.setEnabled(False)
            self.ui.OuterSwitch.setText(QtWidgets.QApplication.translate("MainWindow", "Open Outer Door",None))
            QtWidgets.QApplication.processEvents()
            self.LCDtimer()
            self.starttimer()
            return GPIO.output(Outer,GPIO.HIGH) #Close OuterDoor

如何在每次再次按下按钮而不是使其连续运行时重置计时器? 谢谢。

1 个答案:

答案 0 :(得分:0)

所以2天后,我设法解决了这个问题。确实只缺少一行代码。

要解决这个问题很简单,我需要在执行该功能之前将LCD显示屏设置为120。

举个例子:

-调用按钮打开和关闭外门:

    def OuterControl(self):
        if GPIO.input(Inner) == 0:  # InnerDoorOpen
            return GPIO.output(Outer, GPIO.HIGH), print("Please Close Inner Door")
        elif GPIO.input(Outer) == 1:  # Outer Door Close
            self.ui.OuterSwitch.setText(QtWidgets.QApplication.translate("MainWindow", "Close Outer Door", None))
            QtWidgets.QApplication.processEvents()
            return GPIO.output(Outer, GPIO.LOW)  # Open Outer Door
        elif GPIO.input(Outer) == 0:  # OuterDoor Open
            self.ui.InnerSwitch.setEnabled(False)
            self.ui.OuterSwitch.setText(QtWidgets.QApplication.translate("MainWindow", "Open Outer Door", None))
            QtWidgets.QApplication.processEvents()
            self.LCDtimer()
            self.starttimer()
return GPIO.output(Outer, GPIO.HIGH)

然后设置一个计时器并将LCD编号与该计时器同步:

        self.current_timer = None
        self.LCD_timer = None
        self.i = 121


    def LCDtimer(self):
        if self.LCD_timer:
            self.LCD_timer.stop()
            self.LCD_timer.deleteLater()
        self.LCD_timer = QtCore.QTimer()
        self.ui.Timer.display(120)
        self.LCD_timer.start(0)
        self.LCD_timer.timeout.connect(self.updateLCDNumber)

    def starttimer(self):
        if self.current_timer:
            self.current_timer.stop()
            self.current_timer.deleteLater()
        self.i = 121

        self.current_timer = QtCore.QTimer()
        self.current_timer.setSingleShot(True)
        self.current_timer.start(123000)
        self.current_timer.timeout.connect(self.InnerSwitchOn)

    def updateLCDNumber(self):
        if self.i != 0:
            QtTest.QTest.qWait(1000)
            self.i -= 1
            self.ui.Timer.display(self.i)

    def InnerSwitchOn(self):
        self.ui.InnerSwitch.setEnabled(True)