反序列化时忽略xml属性

Question

我从两个不同的系统收到一个XML，我必须使用C＃将其反序列化。两种xml都应该相同，但不幸的是它们略有不同，而且我无法对它们创建xml的系统产生影响。

xml1

<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<alarm>
  <alarmDetails>
    <dateTime>20180906-121451</dateTime>
  </alarmDetails>
  <deviceDetails>
    <deviceType>abacaxi</deviceType>
  </deviceDetails>
  <position>
    <altitude>1000</altitude>
  </position>
</alarm>

xml2

<?xml version="1.0" encoding="utf-8"?>
<alarm xmlns="http://alarm.com/xsd">
  <alarmDetails>
    <dateTime>20180906-114818</dateTime>
  </alarmDetails>
  <deviceDetails>
    <deviceType>tapioca</deviceType>
  </deviceDetails>
  <position>
    <altitude>1000</altitude>
  </position>
</alarm>

（xml 2在警报标签上有一个附加属性）

我尝试使用以下方法反序列化：

代码

using System.IO;
using System.Xml.Serialization;

namespace ConsoleApp1
{
    class Program
    {
        static void Main(string[] args)
        {
            XmlSerializer serializer = new XmlSerializer(typeof(Alarm));
            StreamReader stream = new StreamReader("C:\\Temp\\xml1.xml");
            Alarm alarmmessage = (Alarm)serializer.Deserialize(stream);
        }
    }


    [XmlRoot(ElementName = "alarmDetails")]
    public class AlarmDetails
    {
        [XmlElement(ElementName = "dateTime")]
        public string DateTime { get; set; }
    }

    [XmlRoot(ElementName = "deviceDetails")]
    public class DeviceDetails
    {
        [XmlElement(ElementName = "deviceType")]
        public string DeviceType { get; set; }
    }

    [XmlRoot(ElementName = "position")]
    public class Position
    {
        [XmlElement(ElementName = "altitude")]
        public string Altitude { get; set; }
    }

    [XmlRoot(ElementName = "alarm")]
    public class Alarm
    {
        [XmlElement(ElementName = "alarmDetails")]
        public AlarmDetails AlarmDetails { get; set; }
        [XmlElement(ElementName = "deviceDetails")]
        public DeviceDetails DeviceDetails { get; set; }
        [XmlElement(ElementName = "position")]
        public Position Position { get; set; }
    }
}

这对于xml1来说是完美的，但是对于xml2却出现此错误：

错误

System.InvalidOperationException
Message=There is an error in XML document (2,2).
Inner Exception 1:
InvalidOperationException: <alarm xmlns='http://alarm.com/xsd'> was not expected.

可能的解决方案

所有这些都不起作用。

XmlRootAttribute

发件人：{" was not expected.} Deserializing Twitter XML

我最后做了这个修改：

static void Main(string[] args)
{
    XmlRootAttribute xRoot = new XmlRootAttribute();
    xRoot.ElementName = "alarm";
    xRoot.IsNullable = true;
    XmlSerializer serializer = new XmlSerializer(typeof(Alarm), xRoot);
    StreamReader stream = new StreamReader("C:\\Temp\\xml2.xml");
    Alarm alarmmessage = (Alarm)serializer.Deserialize(stream);
}

获得与上述相同的错误。

IsNullable = true到XmlRoot

发件人：{" was not expected.} Deserializing Twitter XML

[XmlRoot(ElementName = "alarm", IsNullable = true)]
public class Alarm
{ 
    [XmlElement(ElementName = "alarmDetails")]
    public AlarmDetails AlarmDetails { get; set; }
    [XmlElement(ElementName = "deviceDetails")]
    public DeviceDetails DeviceDetails { get; set; }
    [XmlElement(ElementName = "position")]
    public Position Position { get; set; }
}

与上述错误相同。

XmlAttributeOverrides

发件人：Ignore a property during xml serialization but not during deserialization

static void Main(string[] args)
{
    XmlAttributeOverrides overrides = new XmlAttributeOverrides();
    XmlAttributes attribs = new XmlAttributes();
    attribs.XmlIgnore = true;
    attribs.XmlElements.Add(new XmlElementAttribute("alarm"));
    overrides.Add(typeof(Alarm), "alarm", attribs);
    XmlSerializer serializer = new XmlSerializer(typeof(Alarm), overrides);
    StreamReader stream = new StreamReader("C:\\Temp\\xml2.xml");
    Alarm alarmmessage = (Alarm)serializer.Deserialize(stream);
}

仍然与上述错误相同。

建议？

我还能尝试做些什么？有什么工作方法可以忽略xmlns-Attribut吗？