Question

这是我的SQL：

WHERE 
CASE 
    WHEN (UC.USER = SESSION_USER() AND UC.full_access = 1) 
    THEN (FROS.IsVoided = false) 
    ELSE (FROS.IsVoided = false AND UC.USER = SESSION_USER()) 
END

我需要IF用户=（当前会话用户）并且full_access = 1显示 X 否则 Y ，我可以提供更多代码和表格，但是从常规视图，有人可以发现我犯过的任何常见错误吗？

或者我有这个想法：

WHERE 
IF(UC.USER = SESSION_USER() AND UC.full_access= 1, FROS.IsVoided = false, FROS.IsVoided = false AND UC.USER = SESSION_USER())

WHat是在 WHERE 子句中使用if语句的正确方法吗？

解决方案：

WHERE IF(((SELECT full_access FROM `TABLE` WHERE user = SESSION_USER())= 1), (FROS.IsVoided = false), (FROS.IsVoided = false AND UC.USER = SESSION_USER()))

Answer 1

问题的答案是查询的SELECT部分中的一列：

SELECT (CASE WHEN UC.USER = SESSION_USER() AND UC.full_access = 1 
             THEN 'X' ELSE 'Y'
        END) as what_you_asked_for

我不知道这与您提供的代码有何关系。

Answer 2

以下BigQuery标准SQL示例

#standardSQL
WITH `project.dataset.table` AS (
  SELECT 1 col1, 2 col2, 3 col3 UNION ALL
  SELECT 4, 5, 6
), users_access AS (
  SELECT 'user1@gmail.com' user, 1 full_access UNION ALL
  SELECT 'user2@gmail.com', 0
) 
SELECT col1, col2, col3 
FROM `project.dataset.table` 
WHERE 1 = (SELECT full_access FROM users_access WHERE LOWER(user) = LOWER(SESSION_USER()))
OR (0 = (SELECT full_access FROM users_access WHERE LOWER(user) = LOWER(SESSION_USER()))
AND col1 > 2)

user1@gmail.com的结果：

Row     col1    col2    col3     
1       1       2       3    
2       4       5       6

user2@gmail.com的结果：

Row     col1    col2    col3     
1       4       5       6

user3@gmail.com的结果：

Row     col1    col2    col3     
Query returned zero records.

可以对上面的内容进行如下重构（对于具有full_access = 1或full_access = 0或根本不在列表中的用户具有相同的行为）

#standardSQL
WITH `project.dataset.table` AS (
  SELECT 1 col1, 2 col2, 3 col3 UNION ALL
  SELECT 4, 5, 6
), users_access AS (
  SELECT 'user1@gmail.com' user, 1 full_access UNION ALL
  SELECT 'user2@gmail.com', 0
) 
SELECT * EXCEPT(access) 
FROM `project.dataset.table`, 
  UNNEST([(SELECT full_access FROM users_access WHERE LOWER(user) = LOWER(SESSION_USER()))]) access 
WHERE access = 1
OR (access = 0 AND col1 > 2)

注意：col1 > 2只是虚拟过滤器，实际上应该是针对您的情况考虑的任何过滤器

SQL在SQL查询内部（在WHERE子句内部的CASE / IF）直接创建SQL

2 个答案: