Question

我想通过其他字段模型更新字段

例如，当我选择一名员工时，我想在（hr.employee）中更新其坐标

class hr_employee(models.Model):
    _name = 'hr.employee.transfer'
    _rec_name = 'employee_id'




    def _cron_transfert(self):
        current_date = datetime.now() 
        transfer = self.env['hr.employee.transfer'].search([('date_transfer' ,'>', current_date.strftime('%Y-%m-%d')),('state','=','done')])
        for employee in transfer: 
            employee.address_id = transfer.address_id_new 
            employee.job_id = transfer.job_id_new
            print '-------------------',transfer.job_id_new    


    date_cration = fields.Date(string='Date order', required=True, default=datetime.today())
    date_transfer = fields.Date(string='Date of actual transfer' ,required=True)
    employee_id = fields.Many2one('hr.employee',string='Employee', required=True)
    country_work_id = fields.Many2one('res.country',string='Country', required=True)
    country_id = fields.Many2one('res.country',string='Nationality',  required=True)   
    job_id = fields.Many2one('hr.job',string='Job title',  required=True) 
    state_work_id = fields.Many2one('res.country.state',string='Fed. State', domain="[('country_id', '=', country_work_id)]",  required=True)   
    working_address = fields.Many2one('res.partner',string='Working Address',  required=True)   

    job_id_new = fields.Many2one('hr.job',string='Job title',  required=True) 
    address_id_new = fields.Many2one('res.partner', string='Working Address new',  required=True)




    state = fields.Selection([
        ('draft', 'Draft'),
        ('accept', 'Director Manager'),
        ('done', 'Done'),
        ('cancel', 'Cancel'),
    ], string='Order Status', readonly=True, copy=False, store=True, default='draft')

我想通过此 address_id_new 更改字段 address_id （在'hr.employee中）和 job_id_new

的 job_id 字段（在'hr.employee中）

我在Cron（XML）中添加了函数_cron_transfert，但是如果我手动运行时该错误消失了（ValueError：预期的单例：hr.employee.transfer（37，38）

Answer 1

像这样更改您的功能

    def _cron_transfert(self):
        current_date = datetime.now() 
        transfer = self.env['hr.employee.transfer'].search([('date_transfer' ,'>', current_date.strftime('%Y-%m-%d')),('state','=','done')])
        for employee in transfer: 
            employee.address_id = employee.address_id_new.id 
            employee.job_id = employee.job_id_new.id
            print '-------------------',transfer.job_id_new

Answer 2

感谢所有人我找到了解决方案，而且是

def _cron_emp(self):
    current_date = datetime.now() 
    record= self.env['hr.employee.transfer'].search([('date_transfer' ,'<=', current_date.strftime('%Y-%m-%d')),('state','=','done')])
    for rec in record: 
        rec.employee_id.job_id= transfer.job_id_new
        rec.employee_id.address_id = transfer.address_id_new

从cron odoo更新字段

2 个答案: