假设您有一个表格如下:
CREATE TABLE EMPLOYEE_SALES
(
EMPLOYEE_ID NUMBER,
PRODUCT_ID NUMBER,
SALE_AMOUNT NUMBER
);
并假设它填充如下:
+-------------+------------+-------------+ | EMPLOYEE_ID | PRODUCT_ID | SALE_AMOUNT | +-------------+------------+-------------+ | 1 | 100 | 1.05 | | 1 | 200 | 45.67 | | 2 | 100 | 3.25 | | 2 | 200 | 34.29 | +-------------+------------+-------------+
现在,假设我创建了一个名为SALE_TYPE
的自定义类型,它代表(PRODUCT_ID, SALE_AMOUNT)
元组:
CREATE TYPE SALE_TYPE IS OBJECT
(
PRODUCT_ID NUMBER,
SALE_AMOUNT NUMBER
);
假设我还创建了一个名为SALES_TYPE
的自定义类型,它代表TABLE
SALE_TYPE
:
CREATE TYPE SALES_TYPE IS TABLE OF SALE_TYPE;
我想按EMPLOYEE_SALES
查询EMPLOYEE_ID
表格组。对于每个EMPLOYEE_ID
,我希望创建一个包含该员工销售额的SALES_TYPE
。根据文档,我会做这样的事情:
SELECT
EMPLOYEE_ID,
CAST
(
MULTISET
(
SELECT
PRODUCT_ID,
SALE_AMOUNT
FROM
EMPLOYEE_SALES inner_employee_sales
WHERE
inner_employee_sales.employee_id = employee_sales.employee_id
) AS SALES_TYPE
) AS SALES
FROM
EMPLOYEE_SALES
GROUP BY
EMPLOYEE_ID
我希望这个查询产生这样的结果:
+-------------+------------------------------+ | EMPLOYEE_ID | SALES | +-------------+------------------------------+ | 1 | +------------+-------------+ | | | | PRODUCT_ID | SALE_AMOUNT | | | | +------------+-------------+ | | | | 100 | 1.05 | | | | | 200 | 45.67 | | | | +------------+-------------+ | +-------------+------------------------------+ | 2 | +------------+-------------+ | | | | PRODUCT_ID | SALE_AMOUNT | | | | +------------+-------------+ | | | | 100 | 3.25 | | | | | 200 | 34.29 | | | | +------------+-------------+ | +-------------+------------------------------+
有没有办法在不发出子查询的情况下获得相同的结果(我正在处理的真正的查询比这个人为的例子复杂得多)?例如,有这样的事情:
SELECT
EMPLOYEE_ID,
CAST
(
COLLECT_ALL_RECORDS_WITHIN_THE_CURRENT_GROUP(
PRODUCT_ID,
SALE_AMOUNT
)
AS SALES_TYPE
) AS SALES
FROM
EMPLOYEE_SALES
GROUP BY
EMPLOYEE_ID
答案 0 :(得分:6)
在Oracle 10g中,您可以按如下方式使用COLLECT运算符:
select employee_id,
cast(collect(sale_type(product_id, sale_amount)) as sales_type)
from employee_sales
group by employee_id
答案 1 :(得分:3)
你应该能够编写一个custom aggregate function沿着为11.2和LISTAGG函数之前连接字符串而创建的聚合函数的行。
例如,我可以创建一个EMP_OBJ对象和这些对象的集合(EMP_TBL),并编写一个自定义聚合函数,从一个简单的SQL语句生成一个EMP_TBL集合
创建基本类型
SQL> create type emp_obj as object (
2 empno number,
3 ename varchar2(100)
4 );
5 /
Type created.
SQL> create type emp_tbl
2 as
3 table of emp_obj;
4 /
Type created.
创建我们将用于进行聚合的类型
SQL> ed
Wrote file afiedt.buf
1 CREATE OR REPLACE TYPE emp_tbl_agg AS OBJECT
2 (
3 g_emp_coll emp_tbl,
4 STATIC FUNCTION ODCIAggregateInitialize(sctx IN OUT emp_tbl_agg )
5 RETURN NUMBER,
6 MEMBER FUNCTION ODCIAggregateIterate(self IN OUT emp_tbl_agg ,
7 value IN emp_obj)
8 RETURN NUMBER,
9 MEMBER FUNCTION ODCIAggregateTerminate(self IN emp_tbl_agg,
10 returnValue OUT emp_tbl,
11 flags IN NUMBER)
12 RETURN NUMBER,
13 MEMBER FUNCTION ODCIAggregateMerge(self IN OUT emp_tbl_agg,
14 ctx2 IN emp_tbl_agg)
15 RETURN NUMBER
16* );
17 /
Type created.
SQL> ed
Wrote file afiedt.buf
1 CREATE OR REPLACE TYPE BODY emp_tbl_agg IS
2 STATIC FUNCTION ODCIAggregateInitialize(sctx IN OUT emp_tbl_agg)
3 RETURN NUMBER IS
4 BEGIN
5 sctx := emp_tbl_agg(NULL);
6 sctx.g_emp_coll := new emp_tbl();
7 RETURN ODCIConst.Success;
8 END;
9 MEMBER FUNCTION ODCIAggregateIterate(self IN OUT emp_tbl_agg,
10 value IN emp_obj )
11 RETURN NUMBER IS
12 BEGIN
13 SELF.g_emp_coll.extend();
14 SELF.g_emp_coll(self.g_emp_coll.count) := value;
15 RETURN ODCIConst.Success;
16 END;
17 MEMBER FUNCTION ODCIAggregateTerminate(self IN emp_tbl_agg,
18 returnValue OUT emp_tbl,
19 flags IN NUMBER)
20 RETURN NUMBER IS
21 BEGIN
22 returnValue := self.g_emp_coll;
23 RETURN ODCIConst.Success;
24 END;
25 MEMBER FUNCTION ODCIAggregateMerge(self IN OUT emp_tbl_agg,
26 ctx2 IN emp_tbl_agg)
27 RETURN NUMBER IS
28 BEGIN
29 FOR i IN ctx2.g_emp_coll.FIRST .. ctx2.g_emp_coll.LAST
30 LOOP
31 self.g_emp_coll.extend();
32 self.g_emp_coll(self.g_emp_coll.count) := ctx2.g_emp_coll(i);
33 END LOOP;
34 RETURN ODCIConst.Success;
35 END;
36* END;
SQL> /
Type body created.
声明聚合函数
SQL> create or replace function emp_agg( p_input emp_obj )
2 return emp_tbl
3 aggregate using emp_tbl_agg;
4 /
Function created.
现在使用我们的自定义聚合函数的简单GROUP BY将生成一个EMP_TBL集合
SQL> select deptno, emp_agg( emp_obj( empno, ename ) )
2 from emp
3 group by deptno;
DEPTNO
----------
EMP_AGG(EMP_OBJ(EMPNO,ENAME))(EMPNO, ENAME)
--------------------------------------------------------------------------------
10
EMP_TBL(EMP_OBJ(7782, 'CLARK'), EMP_OBJ(7934, 'MILLER'), EMP_OBJ(7839, 'KING'))
20
EMP_TBL(EMP_OBJ(7369, 'smith'), EMP_OBJ(7902, 'FORD'), EMP_OBJ(7876, 'ADAMS'), E
MP_OBJ(7788, 'SCOTT'), EMP_OBJ(7566, 'JONES'))
30
EMP_TBL(EMP_OBJ(7499, 'ALLEN'), EMP_OBJ(7900, 'SM2'), EMP_OBJ(7844, 'TURNER'), E
DEPTNO
----------
EMP_AGG(EMP_OBJ(EMPNO,ENAME))(EMPNO, ENAME)
--------------------------------------------------------------------------------
MP_OBJ(7698, 'BLAKE'), EMP_OBJ(7654, 'MARTIN'), EMP_OBJ(7521, 'WARD'))