我有一个网站必须对手机具有响应能力。我已经在桌面上创建了它。当我调整浏览器窗口时,它可以完美地在手机上运行,但是当我在真正的手机上对其进行检查时,它对移动视图没有响应。
在我添加以下行之后:
<meta name="viewport" content="width=device-width, initial-scale=1.0, user-
scalable=no">
此jsp页面的元数据。
在我的网站响应手机之后。但是添加此元标记后,jQuery数据表无法正常工作。
所以我的问题是如何同时处理这两个问题?
这是我的数据表代码
function loaddatatable(rows, page, username, merchantId, status, search) {
var table = $('#table1').DataTable({
dom: '<"toolbar">frtip',
paging: false,
info: false,
bDestroy: true,
order: [],
sort: "position",
searching: false,
responsive: true,
sAjaxSource: "ListMerchant.blb?rows=" + rows + "&page=" + page + "&userName="
+ username + "&merchantId=" + merchantId + "&status=" + status + "&search=" + search + "",
columnDefs: [
{
"title": "Merchant Id",
"mData": "merchantId",
"targets": 0
},
{
"title": "User Name",
"mData": "userName",
"targets": 1
}, {
"title": "Channel Type",
"mData": "channeltype",
"targets": 2
}, {
"title": "User Name",
"mData": "channeltype",
"targets": 3
}, {
"title": "Status",
"mData": "status",
"targets": 4
}, {
"title": "Active/Deactive",
"render": function(data, type, full, meta) {
tablelenght = full.fullCount;
return actdectformatter(full);
},
"targets": 5
}, {
"title": "Password Reset",
"render": function(data, type, full, meta) {
return pwresetformatter(full);
},
"targets": 6
}, {
"title": "Edit",
"render": function(data, type, full, meta) {
return editformatter(full);
},
"targets": 7
},
{
"title": "Assign Transaction",
"render": function(data, type, full, meta) {
return assigntxnformatter(full);
},
"targets": 8
}
], initComplete: function(settings, json) {
tablelenght = json.total;
var pagecount = parseInt($('#page').val());
var row = parseInt($('#row').val());
var end = pagecount * row;
var start = (pagecount * row) - row;
if (end > tablelenght) {
end = tablelenght;
}
var maxpage = Math.ceil(tablelenght / row);
$('#tablelength').html(tablelenght);
$('#maxpage').html(maxpage);
$('#start').html(start);
$('#end').html(end);
}
});
}
第一时间数据表已正确加载。当我调用后端操作数据表时,表头无法正确加载。拳头时间数据表。
我检查了检查元素,然后看到自动为标题设置了这种样式
<th class="sorting" tabindex="0" aria-controls="table12" rowspan="1" colspan="1" style="width: 0px; display: none;" aria-label="User Name: activate to sort column ascending">User Name</th>
我应该如何避免这种情况?
答案 0 :(得分:2)
使用以下类样式在每次页面刷新时覆盖当前样式。
<style>
.sorting{
display: table-cell !important;
}
</style>