转换日期时间

Question

我从此查询中获取分钟数

(SELECT (X_GSA_LEAVE_SITE - X_GSA_ARRIVE_ONSITE) * 24 * 60 AS difference_in_minutes 
FROM table_x_gsa_time_stamps 
WHERE X_TIME_STAMPS2X_DISPTCHFE = dfe.objid and rownum=1) Adj_Handle_time,

我需要hh：mm格式..我该如何实现

Answer 1

尝试一下：

SELECT TRUNC(((X_GSA_LEAVE_SITE - X_GSA_ARRIVE_ONSITE) * 24 * 60)/60) || ':' ||
     (((X_GSA_LEAVE_SITE - X_GSA_ARRIVE_ONSITE) * 24 * 60) 
                - TRUNC(((X_GSA_LEAVE_SITE - X_GSA_ARRIVE_ONSITE) * 24 * 60)/60)*60) 
FROM table_x_gsa_time_stamps 
WHERE X_TIME_STAMPS2X_DISPTCHFE = dfe.objid 
and rownum=1

Answer 2

稍微简化的版本：

select x_gsa_arrive_onsite
     , x_gsa_leave_site
     , trunc((x_gsa_leave_site - x_gsa_arrive_onsite) * 24) ||':'||
       trunc(mod((x_gsa_leave_site - x_gsa_arrive_onsite) * 24 * 60, 60)) as onsite_hhmi
from   table_x_gsa_time_stamps ts;

给予

X_GSA_ARRIVE_ONSITE X_GSA_LEAVE_SITE   ONSITE_HHMI
------------------- ------------------ -----------
01-SEP-2018         01-SEP-2018 12:34  12:34
01-SEP-2018         02-SEP-2018 01:23  25:23