Question

我正在尝试制作一个程序，为您提供输入的平均数，总数和最大数。我被困在最大的部分。我的电话号码不在列表中，所以我不知道如何找到最大的电话号码。

num=0 
total=0 
average=0 
count=0 

while True: 
  num=input("enter a number:")
  num=int(num) 
  if num==-999: 
    break 
  total=total + num
  count=count+1 
  biggest = max(total)

average=total/count 

#print the results
print("the total is:", total)
print("the biggest number is:", biggest)
print("the average is:", average)

我希望它最后打印最大的数字。

谢谢

Answer 1

num=0 
total=0 
average=0 
count=0
biggest=0

while True: 
  num=input("enter a number:")
  num=int(num) 
  if num==-999: 
    break 
  total=total + num
  count=count+1 
  if num > biggest:
      biggest = num

average=total/count 

#print the results
print("the total is:", total)
print("the biggest number is:", biggest)
print("the average is:", average)

Answer 2

您可以：

if num > biggest:
   biggest = num

Answer 3

使用不能大于任何输入的值初始化最大值：

import numpy
biggest = -np.inf

替换

biggest = max(total)

作者

biggest = max(biggest, num)

Answer 4

在循环之前初始化变量biggest：

biggest = -9999

应将其初始化为小于程序将要遇到的任何数字的东西。以上假设-9999是一个数字，这通常是一个错误的假设；有更好的方法可以做到这一点，例如评论之一建议

import sys
biggest = -sys.maxint

这是此实现可以表示的最大整数值的负数。

然后在循环体中，更新变量biggest：

biggest = max(biggest, num)

如果num大于biggest，则max(biggest, num)将返回num的值，以便biggest将获得num的值。如果较小，则biggest将保持不变。换句话说，biggest会记住迄今为止看到的最大值。在循环结束时，它将保持看到的最大值，即周期。

Answer 5

在这里将您的代码设置为正确

num=0 
total=0 
average=0 
count=0 
biggest = None  ### added

while True: 
  num=input("enter a number:")
  num=int(num)
  if num==-999: 
    break 
  total=total + num
  count=count+1 

  #biggest = max(total)   Here where was you wrong
  if num > biggest :   #### added
     biggest = num     #### added

average=total/count 

#print the results
print("the total is:", total)
print("the biggest number is:", biggest)
print("the average is:", average)

Answer 6

让我为您分享解决问题的方法。（检查数字为“ -999”后，看看if子句）。随时问您有什么问题！希望对您有帮助

num=0 
total=0 
average=0 
count=0
biggest=0 

while True: 
  num=input("enter a number:")
  num=int(num) 
  if num==-999: 
    break
  if num > biggest:
    biggest = num
  total=total + num
  count=count+1 

average=total/count 

#print the results
print("the total is:", total)
print("the biggest number is:", biggest)
print("the average is:", average)

Answer 7

如果您研究其他方法，您将获得更多功能，甚至对程序进行更多操作，请看一下这段代码，并尝试一些想法，以使您的任务和以后的任务变得更容易 >

numbers = []

print("Enter any non-number to perform calculations.\n")

while True:
    try:
        num = int(input("Enter a number: "))
        numbers.append(num)

    except ValueError:
        break

total = sum(numbers)
average = total/len(numbers)
biggest = max(numbers)

print(f"\nThe total is: {total}")
print(f"The biggest number is: {biggest}")
print(f"The average is: {average}")

(xenial)vash@localhost:~/python$ python3.7 biggest.py
Enter any non-number to perform calculations.

Enter a number: 1
Enter a number: 2
Enter a number: 3
Enter a number: 4
Enter a number: -1
Enter a number: 2
Enter a number: 3
Enter a number: q

The total is: 14
The biggest number is: 4
The average is: 2.0

如何找到列表中没有的最大数字？

7 个答案: